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Solutions

Question

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Calculate the mass percentage of benzene (C₆H₆) and carbon tetrachloride (CCl₄) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride.

Solution

Mass % of benzene

= \frac{mass of benzene}{mass of solution} \times 100 = \frac{22}{22 + 122} \times 100 = \frac{22}{144} \times 100 = 15.28 %

Mass% of carbon tetrachloride = 100 - 15.28
= 84.72%

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