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Haloalkanes And Haloarenes

Question
CBSEENCH12007984

How do the products differ when ethyl bromide reacts separately with aq. KOH and alc. KOH?

Solution

This can be explain in the following ways:

When alkyl chloride react with aqueous KOH it forms alcohol. it is subsitution reaction.

C2H5Cl +KOH(aq.) ---> C2H5OH +KCl

When alkyl chloride react with alcoholic KOH it forms alkene. In this case elimination reaction take place.

C2H5Cl +KOH(alc.) ---> H­2C=CH2 +KCl +H2O