Question
Starting from ethyl bromide, how will you get (i) ethanol (ii) ethylene.
Solution
i) When ethyl bromide react with aq. KOH it forms ethanol.
CH3 -CH2 -Br + KOH (aq.) ---> CH3 -CH2 -OH
ii) When ethyl bromide react with alc. KOH it forms ethylene.
CH3 -CH2 -Br +KOH (alc.) ---> CH2 =CH2