Arrange the following compounds in increasing order of SN1 , respectively.
ClCH2=CHCH2CH3, CH3(Cl)=CHCH2CH3, CH3 = CHCH2 CH2Cl, CH3CH = CH. CHCl CH3
CH3CH = CHCH2CH2Cl < CH3CH = CH.CH(Cl)CH3 ClCH2CH = CH.CH2CH3 < CH3C(Cl) = CHCH2CH3< CH3CH = CH.CH(Cl)CH3< CH3CH = CH CH2CH2Cl.
This is due to the stability of carbonium intermediate.