Question
tetra - Butyl iodide undergoes following reactions:
(CH3)3 Cl+H2O → (CH3)3COH + HI
(CH3)3CI + OH– → (CH3)2 C = CH2 + H2O + I–
Give reasons.
Solution
In a nucleophilic solvent, a tertiary RX undergoes an SN1 solvolysis in the absence of a strong base.