Question
Reduce the following Boolean Expression using K-Map:
F(A,B,C,D) = ∑(2,3,4,5,6,7,8,10,11)
Solution
F(A,B,C,D) = A’B+AB’C+AB’D’
Reduce the following Boolean Expression using K-Map:
F(A,B,C,D) = ∑(2,3,4,5,6,7,8,10,11)
F(A,B,C,D) = A’B+AB’C+AB’D’
Write the SOP form of a Boolean Function F, which is represented in a truth table as follows:
|
X |
Y |
Z |
F |
|
0 |
0 |
0 |
1 |
|
0 |
0 |
1 |
0 |
|
0 |
1 |
0 |
1 |
|
0 |
1 |
1 |
0 |
|
1 |
0 |
0 |
1 |
|
1 |
0 |
1 |
0 |
|
1 |
1 |
0 |
0 |
|
1 |
1 |
1 |
1 |
Reduce the following Boolean Expression using K-Map:
F(A,B,C,D) = ∑(2,3,4,5,6,7,8,10,11)
Mock Test Series
