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Boolean Algebra

Question

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Verify the following using Boolean Laws.
X + Y' = X.Y+ X.Y'+ X'.Y'

Solution

L.H.S
=X + Y'
=X.(Y+Y')+ (X + X').Y'
=X.Y + X.Y' + X.Y' +X'.Y'
=X.Y + X.Y' + X'.Y'
=R.H.S

Some More Questions From Boolean Algebra Chapter

Write the Boolean Expression for the result of the Logic Circuit as shown below:

Derive a Canonical POS expression for a Boolean function F, represented by the following truth table:

P Q R F(P, Q, R)

0 0 0 0

0 0 1 1

0 1 0 1

0 1 1 0

1 0 0 0

1 0 1 0

1 1 0 1

1 1 1 1

Reduce the following Boolean Expression to its simplest form using K-Map:
F(X,Y,Z,W)= (2,6,7,8,9,10,11,13,14,15)

Verify the following using Boolean Laws.
X + Y' = X.Y+ X.Y'+ X'.Y'

Derive a Canonical SOP expression for a Boolean function F, represented by the following truth table :

A B C F(A,B,C)

0 0 0 1

0 0 1 0

0 1 0 0

0 1 1 1

1 0 0 1

1 0 1 0

1 1 0 0

1 1 1 1

Draw the Logic Circuit for the following Boolean Expression :
(U + V').W' + Z

Reduce the following Boolean Expression to its simplest form using Kâ€Map :
F(X,Y,Z,W) = ∑(0,1,6,8,9,l0,11,12,15)

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