ARR[15][20] is a two-dimensional array, which is stored in the memory along the row with each of its elements occupying 4 bytes. Find the address of the element ARR[5][15], if the element ARR[10][5] is stored at the memory location 35000.
ROW MAJOR:
Loc(ARR[I][J]) =BaseAddress + W [( I – LBR)*C + (J – LBC)]
(where W=size of each element = 4 bytes, R=Number of
Rows=15, C=Number of Columns=20 )
Assuming LBR = LBC = 0
LOC(ARR[10][5])
35000 = BaseAddress + W(I*C + J)
35000 = BaseAddress + 4(10*20 + 5)
35000 = BaseAddress + 4(205)
35000 = BaseAddress + 820
BaseAddress = 35000 - 820
= 34180
LOC(ARR[5][15])= BaseAddress + W(I*C + J)
= 34180 + 4(100 + 15)
= 34180 + 4 x 115
= 34180 + 460
= 34640