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Computer Science With C++ Chapter 3 Classes And Objects

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    NCERT Solution For Class 12 Computer And Communication Technology Computer Science With C++

    Classes And Objects Here is the CBSE Computer And Communication Technology Chapter 3 for Class 12 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 12 Computer And Communication Technology Classes And Objects Chapter 3 NCERT Solutions for Class 12 Computer And Communication Technology Classes And Objects Chapter 3 The following is a summary in Hindi and English for the academic year 2021-2022. You can save these solutions to your computer or use the Class 12 Computer And Communication Technology.

    Question 1
    CBSEENCO12011568
    Wired Faculty App

    Write the definition of a class BOX in C++ with following description:

    Private Members

    - BoxNumber    // data member of integer type
- Side         // data member of float type
- Area         // data member of float type
- ExecArea()   // Member function to calculate and assign
               // Area as Side * Side

Public Members

- GetBox()     // A function to allow user to enter values of
               // BoxNumber and Side. Also, this
               // function should call ExecArea() to calculate
               // Area
- ShowBox()    // A function
               // and Area
    Solution

    The definition of a class Box in C++ given,

    class BOX
{
	int BoxNumber;
	float Side;
	float Area;
	void ExecArea(){ Area=Side*Side;}
public:
	void GetBox();
	void ShowBox();
};
void BOX::GetBox()
{
	cin>>BoxNumber>>Side;
	ExecArea();
}
void BOX::ShowBox()
{
	cout<<BoxNumber<<' '<<Side<<' '<<Area<<endl;
}
    Question 2
    CBSEENCO12011618
    Wired Faculty App

    Write the definition of a function FixPay(float Pay[], int N) in C++, which should modify each element of the array Pay having N elements, as per the following rules:

    Existing Value of Pay Pay to be changed to
    If less than 100000 Add 25% in the existing value
    If >=100000 and <20000 Add 20% in the existing value
    If >=200000 Add 15% in the existing value

    Solution
    void FixPay(float Pay[ ], int N)
{
	for (int i=0;i<N;i++){
		if(Pay[i]<100000){
			Pay[i]+= 0.25 * Pay[i];
		}
		else if (Pay[i]>=100000 && Pay[i]<20000){
			Pay[i]+= 0.2 * Pay[i];
		}
		else if(Pay[i]>=200000){
			Pay[i]+= 0.15 * Pay[i];
		}
	}
}

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