Chemistry Ii Chapter 14 Biomolecules
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    NCERT Solution For Class 12 Chemistry Chemistry Ii

    Biomolecules Here is the CBSE Chemistry Chapter 14 for Class 12 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 12 Chemistry Biomolecules Chapter 14 NCERT Solutions for Class 12 Chemistry Biomolecules Chapter 14 The following is a summary in Hindi and English for the academic year 2021-2022. You can save these solutions to your computer or use the Class 12 Chemistry.

    Question 1
    CBSEENCH12009461

    Glucose or sucrose are soluble in water but cyclohexane or benzene (simple six membered ring compounds) are insoluble in water. Explain.

    Solution

    Molecules which have polar nature are capable to form hydrogen bond are generally soluble in water. In sucrose and glucose hydroxyl groups are present, which is polar in nature. Therefore, they are involved in intermolecular hydrogen bonding with water molecules, so these compounds are readily soluble in water. On other hand benzene and cyclohexane are hydrocarbons. They do not have any polar group so they cannot make hydrogen bonds with water. 

    Question 2
    CBSEENCH12009462

    What are the expected products of hydrolysed of lactose?

    Solution
    Upon hydrolysis, lactose gives equivalent amounts of D(+) glucose and D(+) galactose.


    Question 3
    CBSEENCH12009463

    How do you explain the absence of aldehyde group in the penta acetate of D-glucose?

    Solution

    Glucose reacts with hydroxylamine to form an oxime. where as, the penta acetate of glucose does not react with hydroxyl amine indicating the absence of free CHO group.

    Question 4
    CBSEENCH12009464

    The melting points and solubility of water of amino acids are generally higher than that of the corresponding halo acids. Explain.

    Solution

    Amino acids are dipolar in nature (+NH3-CHR-COO-) and have strong dipolar interaction. Amino acids have amino (basic) group and carboxylic (acidic) group. A proton which comes from carboxylic group is accepted by amino group. Thus amino acid exists in the form of Zwitter ion.


    Due to this ionic form, amino acids become crystalline solids and due to this salt like structure, show higher melting point.

    Question 5
    CBSEENCH12009465

    Where does the water present in the egg go after the boiling the egg?

    Solution

    Denaturation of proteins is a process in which physical and biological properties of protein without changing the chemical composition of protein. In an egg denaturation of protein is the coagulation of albumin present in the white of an egg. When egg is boiled in water, the globular proteins present in it changes to a rubber like insoluble mass which absorbs all water present in the egg.

    Question 6
    CBSEENCH12009466

    Why cannot vitamin C be stored in our body?

    Solution

    Vitamin C is a water soluble vitamin also vitamin C is rapidly absorbed from intestine. Since it is water soluble, it is not stored in the body and excess amount of vitamin C removed through urine.

    Question 7
    CBSEENCH12009467

    What products would be formed when a nucleotide from DNA containing thymine is hydrolysed?

    Solution

    When a nucleotide from the DNA containing thymine is hydrolyzed, thymine β-D-2- deoxyribose and phosphoric acid are obtained as products.

    Question 8
    CBSEENCH12009468

    When RNA is hydrolysed, there is no relationship among the quantities of different bases obtained. What does this fact suggest about the structure of RNA?

    Solution

    Complete hydrolysis of RNA yields a pentose sugar(D-ribose), phosphoric acid and nitrogen containing heterocyclic compounds (called bases). Such as guanine (G), cytosine (C), Uracil (U), Adenine (A).
    There is no relationship among the quantities of four bases obtained on complete hydrolysis of RNA. It is because base sequence in RNA is not fixed but depend on base sequence in DNA i.e., the base sequence in a specific RNA is controlled by that of DNA which is controlling RNA synthesis (i.e., transcription). The base sequence in DNA indirectly controls the sequence of amino acids in the protein.

     

    Question 9
    CBSEENCH12009469

    What is a biomoiecule?

    Solution
    i) Biomolecules are molecules that occur naturally in living organisms. Biomolecules include macromolecules like proteins, carbohydrates, lipids and nucleic acids. 
    ii) It also includes small molecules like primary and secondary metabolites and natural products.
    iii) Biomolecules consists mainly of carbon and hydrogen with nitrogen, oxygen, sulphur, and phosphorus. Biomolecules are very large molecules of many atoms, that are covalently bound together.
    Question 10
    CBSEENCH12009470

    Define carbohydrates.

    Solution

    Carbohydrates are primarily produced by plants and form a very large group of naturally occurring organic compounds. Some common examples are cane sugar, glucose, starch, etc. They have the general formula Cn(H2O)n.


    Question 11
    CBSEENCH12009471

    Give one example each of (i) Reducing sugar and (ii) Non-reducing sugar.

    Solution
    (i) Glucose is reducing sugar.
    (ii) Sucrose is non- reducing sugar.
    Question 12
    CBSEENCH12009472

    Name the anomers of glucose.

    Solution
    The anomers of glucose are α-D-glucose and β-D-glucose.
    Question 13
    CBSEENCH12009473

    State two characteristics of monosaccharides.

    Solution
    i) Monosaccharides are white crystalline solids, sweet in taste.
    ii) Monosaccharides are reduce by Tollens reagent.
    Question 14
    CBSEENCH12009474

    Name a carbohydrate containing five carbon atoms per molecule.

    Solution
    D-ribose contain five carbon atoms per molecule.
    Question 15
    CBSEENCH12009475

    Name the monomers of starch.

    Solution

    α-D-(+)-glucose

    Question 16
    CBSEENCH12009476

    Name the polysaccharides that is stored in the liver of animals.

    Solution
    Glycogen is a polysaccharides which stored in the liver of animal.
    Question 17
    CBSEENCH12009477

    What do you understand by the term gycosidic linkage?

    Solution

    The two monosaccharides are joined together by an oxide linkage formed by the loss of a water molecule. Such a linkage between two monosaccharide units through oxygen atom is called glycosidic linkage.

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    Question 18
    CBSEENCH12009478

    What are the hydrolytic products of lactose?

    Solution
    Hydrolytic product of lactose are D-Glucose and D-Galactose.
    Question 19
    CBSEENCH12009479

    What is meant by inversion of sugar?

    Solution
    Sugar on hydrolysis give a mixture of D-glucoseand D-fructose which is laevorotatoy whereas sucrose is dextrorotatory. This inversion of optical rotation is called inversion of sugar.
    Question 20
    CBSEENCH12009480

    Why is cellulose not a food for human beings?

    Solution
    Cellulose is not a food for human being because humans do not have the necessary enzymes to hydrolyse (digest) it.
    Question 21
    CBSEENCH12009481

    Name three useful products that can be obtained from cellulose.

    Solution
    Celluloid, rayon, cellulose acetate, gun cotton.
    Question 22
    CBSEENCH12009482

    What are monosaccharides?

    Solution

     

    A carbohydrate that cannot be hydrolysed further to give simpler unit of polyhydroxy aldehyde or ketone is called a monosaccharide. Example: Glucose 
    Question 23
    CBSEENCH12009483

    What are reducing sugars?

    Solution

    A reducing sugar is any sugar that is capable of acting as a reducingagent because it has a free aldehyde group or a free ketone group. All monosaccharides are reducing sugars. 

    Question 24
    CBSEENCH12009484

    Which carbohydrate is called grape sugar? Give its condensed structural formula.

    Solution
    Glucose is called grape sugar. Its condensed structural formula is,

    Question 25
    CBSEENCH12009485

    Write two main functions of carbohydrates in plants. 

    Solution

    (i) They serve as structural materials for cell walls. For example, the polysaccharide cellulose is the chief constituent of the plant cell wall.
    (ii) Carbohydrates act as biofuels and provide energy for different functioning.

    Question 26
    CBSEENCH12009486

    Classify the following into monosaccharides and disaccharides: Ribose, 2-deoxy-ribose, maltose, galactose, fructose and lactose. 

    Solution

    Mono-saccharides: Ribose, 2-deoxyribose, galactose, fructose.
    Di-saccharides: maltose, lactose.

    Question 27
    CBSEENCH12009487

    What happens when sucrose is boiled with dilute HCl?

    Solution
    Sucrose is hydrolysed to give glucose and fructose in equal amounts.
    stack straight C subscript 12 straight H subscript 22 straight O subscript 11 with Sucrose below plus space straight H subscript 2 straight O space space rightwards arrow with HCl space left parenthesis dil right parenthesis on top space stack straight C subscript 6 straight H subscript 12 straight O subscript 6 with Glucose below space plus space stack straight C subscript 6 straight H subscript 12 straight O subscript 6 with Fructose below
    Question 28
    CBSEENCH12009488

    Give one reaction to show the presence of five hydroxyl groups in glucose.

    Solution
    The reaction with acetic anhydride gives penta acetate confirms the presence of five OH groups.


    Question 29
    CBSEENCH12009489

    How will you prove that all the carbon atoms of a glucose are in a straight chain?

    Solution
    The reaction of glucose with HI gives n-Hexane and it proves that all six carbon atoms are in a straight chain.

    Question 30
    CBSEENCH12009490
    Question 31
    CBSEENCH12009491
    Question 33
    CBSEENCH12009493

    What happens when starch is boiled with dil. HCl?

    Solution
    When starch is boiled with dil. HCl it produces glucose. i.e.,
    (C6H10O5)n +HCl ---> (C6H12O6)n

    Question 34
    CBSEENCH12009494

    What happens when cellulose is heated by dil. H2SO4?

    Solution
    When cellulose is heated by dil. H2SO4. It gets hydrolysed into D-glucose.

    Question 35
    CBSEENCH12009495

    Draw the open chain structure of glucose.

    Solution

    Structure of glucose

    Question 36
    CBSEENCH12009496

    Define mutarotation.

    Solution

    Mutarotation is the change in the optical rotation because of the change in the equilibrium between two anomers, when the corresponding stereocenters interconvert. Cyclic sugars show mutarotation as α and β anomeric forms interconvert.

    Question 37
    CBSEENCH12009497

    Draw the structure of the α-glucose and β-glucose.

    Solution

    Structure of the α-glucose and β-glucose.

    Question 38
    CBSEENCH12009498

    Which of the following disaccharides contains a glycosidic linkage between glucose and glucose.

    i)Sucrose
    ii)Maltose
    iii)Lactose

    Solution
    ii) Maltose contains a glycosidic linkage between glucose and glucose.
    Question 39
    CBSEENCH12009499

    Which of the following disaccharides contains a glycosidic linkage between glucose and glucose Sucrose, Maltose, Lactose?

    Solution
    Maltose contains a glycosidic linkage between glucose and glucose.

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    Question 40
    CBSEENCH12009500

    What are the hydrolysis products of
    (i) sucrose and (ii) lactose?

    Solution

    Sucrose on hydrolysis gives glucose and fructose.
    (i) stack straight C subscript 12 straight H subscript 22 straight O subscript 11 with sucrose below space plus space straight H subscript 2 straight O space space rightwards arrow with Invertase on top space stack straight C subscript 6 straight H subscript 12 straight O subscript 6 with glucose below space plus space stack straight C subscript 6 straight H subscript 12 straight O subscript 6 with fructose below
    Lactose on hydrolysis gives glucose and galactose.
    (ii) stack straight C subscript 12 straight H subscript 22 straight O subscript 11 with lactose below space plus space straight H subscript 2 straight O space space rightwards arrow with Lactase on top space stack straight C subscript 6 straight H subscript 12 straight O subscript 6 with glucose below space plus space stack straight C subscript 6 straight H subscript 12 straight O subscript 6 with galactose below

    Question 41
    CBSEENCH12009501

    Name the water insoluble fraction of starch. Name the monomer of this.

    Solution
    Amylopectin is a water insoluble fraction of starch. It is a polymer of straight alpha-D-glucose.
    Question 42
    CBSEENCH12009502
    Question 43
    CBSEENCH12009503

    Amylose and cellulose are both straight chain polysaccharides containing only D-glucose units. What is the structural difference between the two?

    Solution
    Amylose is a polymer of α-anomer of D-glucose while cellulose is a polymer of β-anomer of D-glucose.
    Question 44
    CBSEENCH12009504

    Name any two products derived from cellulose.

    Solution

    (i) Rayon: used in textile industry.
    (ii) Gun cotton: used as an explosive.

    Question 45
    CBSEENCH12009505

    Give one test to distinguish glucose and fructose.

    Solution
    Furfural test is given by fructose only, hence it is used to distinguish glucose and fructose.
    Fructose (1 mL) + 1% α-Naphthol (alc.) (1 mL)
    plus space HCl thin space left parenthesis 6 space mL right parenthesis space rightwards arrow with Boil on top space Violet space colour

    Question 46
    CBSEENCH12009506

    How many members (atoms) will constitute the pyranose ring of glucose?

    Solution
    Pyranose ring of glucose is a six membered ring which contains five carbon atoms and one oxygen atom.
    Question 47
    CBSEENCH12009507

    What is the basic difference betweeen starch and cellulose?

    Solution
    Starch is the polymer of α-glucose while the cellulose is the polymer of β-glucose.
    Question 48
    CBSEENCH12009508

    Why is glucose given to the patient under exhausation?

    Solution
    Gulcose is major source of energy. When glucose is directly passes into the blood stream to the patient. It provide energy to cells particularly of brain and nervous system.
    Question 49
    CBSEENCH12009509

    What is the action of bromine water on:
    (i) glucose, (ii) fructose?

    Solution
    Glucose gets oxidised to gluconic acid when it is treated with bromine water.

    Fructose does not react with bromine water.
    Question 50
    CBSEENCH12009510

    What are the products obtained on the fermentation of glucose?

    Solution
    On fermentation, glucose is converted into ethanol and carbon dioxide.
    stack straight C subscript 6 straight H subscript 12 straight O subscript 6 with Glucose below space rightwards arrow with Fermentation on top space space stack 2 straight C subscript 2 straight H subscript 5 OH with Ethanol below space plus space 2 CO subscript 2
    Question 51
    CBSEENCH12009511

    What is an amino acid? Give one example.

    Solution

    Amino acids contain amino (–NH2) and carboxyl (–COOH) functional groups. For example glycine.

    Question 52
    CBSEENCH12009512

    Write the structural formula of a Zwitter ion.

    Solution

    Structural formula of Zwitter ion.

    Question 53
    CBSEENCH12009513

    How do amino acids form proteins?

    Solution
    Proteins are the polymers of α-amino acids and they are connected to each other by peptide bond or peptide linkage. Therefore, ehen α-amino acids undergo condensation reaction between amino group of one acid and carboxylic group of another acid proteins are formed.

     

    Question 54
    CBSEENCH12009514

    What are the monomers constituting proteins?

    Solution
    A total of 20 amino acids like glycine and alanine are the monomers  constitute proteins.
    Question 55
    CBSEENCH12009515

    In what respect would any two naturally occurring amino acids differ from one another?

    Solution
    All the naturally occurring amino acids are straight alpha-amino acids. They are only differ by in the alkyl group.
    Question 56
    CBSEENCH12009516

    Describe the bonds responsible for the primary structure of proteins.

    Solution
    Proteins are the most abundant biomolecules of the living system. Proteins are the polymers of amino acids. The amino acids are joined together through peptide bonds or peptide linkage in a definite sequence to form primary structure of proteins known as peptide chains.
    Question 57
    CBSEENCH12009517

    Describe the bonds responsible for the secondary structure of proteins.

    Solution

    The secondary structure of protein refers to the shape in which a long polypeptide chain exist. The structure arise due to the regular folding of the backbone of the polypeptide chain due to hydrogen bonding between  -NH- and   groups of the peptide bond.
                              

    Question 58
    CBSEENCH12009518

    Name two important secondary structural forms for a protein.

    Solution
    α-helix and β-pleated sheet.
    Question 59
    CBSEENCH12009519

    What type of bonding helps in stabilising the α-helix structure of proteins?

    Solution
    In the α-helix configuration, a polypeptide chain forms all possible hydrogen bonds by twisting into a right handed screw (helix) with -NH group of each amino acid residue hydrogen bonded to the 
     of an adjacent turn of the helix.
    Question 60
    CBSEENCH12009520

    What type of bonding occurs in β-pleated sheet?

    Solution
    In β-pleated sheet all peptide chains are strectched out to nearly maximum extension and then laid side by side which are held together by intermolecular hydrogen bonds. 
    Question 61
    CBSEENCH12009521

    What type of bonding occurs in globular proteins?

    Solution
    In globular proteins following bonding are occur;
    i) hydrogen bonding
    ii) disulphide linkage
    iii)Van der waals 
    iv)electrostatic forces of attraction.
    Question 62
    CBSEENCH12009522

    What happens when a protein is denatured?

    Solution
    The protein loses its biological activity when it is denatured.
    Question 63
    CBSEENCH12009523

    Give one example of denatured protein. 

    Solution

    The coagulation of egg white on boiling is a example of denaturation.

    Question 64
    CBSEENCH12009524

    What are enzymes?

    Solution

    Enzymes are proteins that catalyze biological reaction. They are very specific in nature and catalyze only a particular reaction for a particular substrate. Enzymes are usually named after a particular. For example, the enzyme used to catalyses  the hydrolysis of maltose in glucose is named as maltase. 
    straight C subscript 12 straight H subscript 22 straight O subscript 11 space rightwards arrow with space space space space space Maltase space space space space space on top space 2 straight C subscript 6 straight H subscript 12 straight O subscript 6
to the power of maltose space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space glucose end exponent

    Question 65
    CBSEENCH12009525
    Question 66
    CBSEENCH12009526

    Name the enzyme that dissolves blood clots.

    Solution
    Streptokinase.
    Question 67
    CBSEENCH12009527

    Write the names of enzymes whose deficiency causes albinism and phenyl ketone urea.

    Solution
    i) Albinism is a disease caused by the deficiency of enzyme tyrosinase.
    ii) Phenyl ketone urea is a disease caused by the deficiency of enzyme Phenylalanine hydroxylase.
    Question 68
    CBSEENCH12009528

    Write the name and the structure of the simplest amino acid which can show optical activity.

    Solution
    Alanine is simplest amino acid which can show optical activity.
    Structure:


    Question 69
    CBSEENCH12009529

    What do you understand by Zwitter ion?

    Solution
    Zwitter ion is a dipolar ion formed by the transfer of proton from —COOH group to —NH2 group within an amino acid molecule.

    Question 70
    CBSEENCH12009530

    Write the structure of Zwitter ion formed from alanine.

    Solution

     Zwitter ion formed fromed by alanine.

    Question 71
    CBSEENCH12009531

    In the dipeptide Glycylalanine( Gly-ala), which amino acid has a free amino group and which has a free carboxyl group?

    Solution
    In Glycylalanine ( gly-ala), glycine has a free amino while alanine has a free carboxyl group.

    Question 72
    CBSEENCH12009532
    Question 73
    CBSEENCH12009533

    Give an example of irreversible protein denaturation.

    Solution

     

    Curding of milk which is caused due to the formation of lactic acid. An example of irreversible protein denaturation.
    Question 74
    CBSEENCH12009534
    Question 75
    CBSEENCH12009535

    What is the importance of amino acids to us?

    Solution

    Proteins are the most abundant biomolecules of the living system. They occur in every part of the body and form the fundamental basis of structure and fuctions of life. They are also required for growth and maintenance of body. Amino acid is monomer of protein, thus they are required for formation of proteins. 

    Question 76
    CBSEENCH12009536

    What do you mean by peptide bond?

    Solution

    Peptide linkage is an amide formed between -COOH group and -NH2 group. The reaction of between two molecules of similar or different amino acids, proceeds through the combination of the amino group of one molecule with the carboxyl group of the other. This results in the elimination of a water molecule and formation of a peptide bond -CO-NH-.

    Question 77
    CBSEENCH12009537

    What is renaturation of protein?

    Solution

    The original structure of a protein is a three dimensional structure. The process of returning a denatured protein structure to its original structure and normal level of biological activity is known as renaturation of protein.

    Question 78
    CBSEENCH12009538

    Which enzyme regulates the blood sugar level in the body?

    Solution
    Insulin regulates the blood sugar level in the body.
    Question 79
    CBSEENCH12009539

    What are nucleic acids?

    Solution
    Nucleic acids are complex acids occurring in all living cells and are composed of a phosphoric acid group, a carbohydrate, two purines and two pyrimidines.

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    Question 80
    CBSEENCH12009540

    What is meant by Nucleotide?

    Solution
    Nucleotide: It is the phosphate ester of nucleoside. It is made up of three parts, phosphoric acid, pentose sugar, and heterocyclic compounds, (Purines and Pyrimidines).
    Question 81
    CBSEENCH12009541

    What do you mean by Nucleoside?

    Solution
    A nucleoside consists of a nitrogenous base covalently attached to a sugar (ribose or deoxyribose) but without the phosphate group. Examples adenosine, thymidine etc.
    Question 82
    CBSEENCH12009542

    What is meant by RNA and DNA?

    Solution
    The nucleic acids are of two types: deoxyribonucleic acid (DNA) and ribonucleic acid (RNA). They differ mainly in the type of sugar they contain. RNA contains D-ribose whereas DNA contains deoxyribose.
    Question 83
    CBSEENCH12009543

    What is the difference between ribose and deoxyribose?

    Solution
    Both are pentoses but deoxyribose has only hydrogen atoms at position 2. Such as hydroxyl group is missing, where as in ribose hydroxyl group bonded to 2 position.

    Question 84
    CBSEENCH12009544

    What are different types of RNA found in the cell?

    Solution

    There are three types of RNA found in cell.
    i) messenger RNA (m-RNA)
    ii) ribosomal RNA (r-RNA)
    iii) transfer RNA (t-RNA).

     

    Question 85
    CBSEENCH12009545

    What type of bonds hold a DNA double helix together?

    Solution
    The two chains of a double helix are held together by hydrogen bonds between specific bases in each chain. A guanine base (G) is linked to cytosine (C) in the opposite chain with hydrogen bonds. Similarly, an adenine base (A) is linked to thymine base (T) in the opposite chain. 

    Question 86
    CBSEENCH12009546

    Where in the higher cells in the DNA molecules mainly located?

    Solution
    In higher cells, the DNA is mainly located in the nucleus, within the chromosome, while small amount of DNA is present in the cytoplasm. 
    Question 87
    CBSEENCH12009547

    Name two purines bases in the nucleic acid.

    Solution

    The two purines bases are:
    (i) Adenine, (A),       (ii) Guanine (G).

    Question 88
    CBSEENCH12009548

    Name the pyrimidine bases present in ribonucleic acid.

    Solution
    The pyrimidine bases present in ribonucleic acid are:
    (i) Uracil (U), (ii) Cytosine (C).
    Question 89
    CBSEENCH12009549

    How many hydrogen bond are present between:
    (i) A and T
    (ii) C and G in a double helix structure?

    Solution

    (i) Between A and T, there exist two hydrogen bonds.
    (ii) Three hydrogen bonds are present between C and G.

    Question 90
    CBSEENCH12009550

    Define DNA replication is Semi conservative ?

    Solution
    DNA replication is semi conservative means only half of the parental DNA is conserved and only one strand is synthesised.
    Question 91
    CBSEENCH12009551

    What do you understand by DNA replication?

    Solution

    The process of a making an identical copy of a DNA by using existing DNA as template for the synthesis of new DNA strands.

    Question 92
    CBSEENCH12009552

    Name the base that is found in nucleotide of RNA only.

    Solution
    Uracil is found in RNA only.
    Question 93
    CBSEENCH12009553

    What is codon?

    Solution
    A sequence of three nucleotides which together form a unit of genetic code in a DNA or RNA molecule.
    Question 94
    CBSEENCH12009554

    What are vitamins?

    Solution
    These are organic substances which are required on the diet in small amounts to perform specific biological functions for normal maintenance of optimum growth and health of the organism known as vitamins. For example, Vitamin A, Vitamin B etc.
    Question 95
    CBSEENCH12009555
    Question 96
    CBSEENCH12009556
    Question 97
    CBSEENCH12009557

    Name the vitamin whose deficiency causes scurvy.

    Solution

    Vitamin C

    Question 98
    CBSEENCH12009558
    Question 99
    CBSEENCH12009559
    Question 100
    CBSEENCH12009560

    Give one source and one use of vitamin B6.

    Solution
    Vitamin B6 is present in cereal grains, yeast, egg and meat. It prevents nervous disturbance and convulsions.
    Question 101
    CBSEENCH12009561

    Which vitamin is linked with anti-sterility?

    Solution
    Vitamin E.
    Question 102
    CBSEENCH12009562

    Write the chemical names of vitamin E and C.

    Solution

    Vitamin E—Tocopherols 
    Vitamin C—Ascorbic acid.

    Question 103
    CBSEENCH12009563

    Give the importance of vitamin C.

    Solution
    It is used to prevent the diseases like pyorrhoea (in teeth), scurvy and anaemia.
    Question 104
    CBSEENCH12009564

    The deficiency of which vitamin causes the disease 'pernicious anaemia'.

    Solution
    cyanocobalamin i.e., Vitamin B12.
    Question 105
    CBSEENCH12009565

    Deficiency of which vitamin causes beri-beri?

    Solution
    Vitamin B.
    Question 106
    CBSEENCH12009566

    Fresh tomatoes are a better source of vitamin C than those which have been stored for sometime. Explain. 

    Solution
    On prolonged exposure to air, vitamin C present in tomatoes is destroyed due to aerial oxidation.
    Question 107
    CBSEENCH12009567

    Why is vitamin 'B' called vitamin B complex?

    Solution
    It is a group of vitamins including vitamin B1, B2, B6, B12 folic acid, nicotinic acid, pantothenic acid and biotin etc.
    Question 108
    CBSEENCH12009568

    State the importance of vitamin D.

    Solution
    It regulates the absorption of calcium and phosphate from intestines and promotes the formation of bone. Deficiency of vitamin D results in soft bones in children (rickets).

    Question 109
    CBSEENCH12009569

    Why are carbohydrates generally optically active?

    Solution
    Their molecules are chiral because of the presence of many asymmetric carbon atom. Thus, carbohydrates are generally optically active.
    Question 110
    CBSEENCH12009570

    What is the difference between ribose and 2-deoxyribose sugars?

    Solution
    In ribose C2 carbon atom is linked to one H-atom and one hydroxyl group while in 2-deoxyribose, it is linked with both H-atom and no hydroxyl group.

    Question 111
    CBSEENCH12009571

    Name a polysaccharide which is stored in the liver of animals as food reserve.

    Solution
    Glycogen (a polymer of D-glucose). 
    Question 112
    CBSEENCH12009572

    What do the following abbreviations represent?
    (a) ala,       (b) val,     (c) leu,    (d) gly.  

    Solution
    Abbreviations represent
    (a) alanine (b) valine (c) leucine (d) glycine 
    Question 114
    CBSEENCH12009574

    What is glycogen? How is it different from starch?

    Solution
    Glycogen is a polysaccharide. It is a polymer of D-glucose. It stores food in animals and human beings.
    Glycogen and starch differ in the type of glycoside bond that joins the D(+) glucose monomers and the amount of chain branching. When the body needs glucose, enzymes break down to glucose.


     


    Question 115
    CBSEENCH12009575

    What is the basic structural difference between starch and cellulose?

    Solution
    Cellulose is a straight chain polysaccharide composed only of β-D-glucose units which are joined by glycosidic linkage between C1 of one glucose unit and C4 of the next glucose unit. On other hand starch is a branched chain polymer of α-glucose and consists of two components Amylose(water soluble) and Amylopectin (water insoluble).
    Question 116
    CBSEENCH12009576

    In what ways does starch show similarity with cellulose?

    Solution

    Starch and cellulose both are polysaccharides. They show similarity in the following ways:
    (i) Both starch and cellulose do not reduce Fehling’s solution or Tollen’s reagent.
    (ii) They do not form osazone.
    (iii) Both are amorphons solid.
    (iv) Both are polymers of D-glucose.

    Question 117
    CBSEENCH12009577

    What happens when D-glucose is treated with the following reagents?
    Hi.

    Solution

    Glucose on prolonged heating with HI, it forms n-hexane.

    Question 118
    CBSEENCH12009578

    What happens when D-glucose is treated with the following reagents?
    Bromine water

    Solution

    Glucose gets oxidised to six carbon carboxylic acid (gluconic acid) on reaction with a mild oxidising agent like bromine water.

    Question 119
    CBSEENCH12009579

    What happens when D-glucose is treated with the following reagents?
    HNO3.

    Solution

    On being treated with HNO3, D-glucose is converted to saccharic acid.

    Sponsor Area

    Question 120
    CBSEENCH12009580

    Enumerate the reactions of D-glucose which cannot be explained by its open chain structure.

    Solution

    The following reactions cannot be explained by its open chain structure:
    (i) Despite having an aldehydic group, glucose does not give Schiff’s test and it does not react with sodium bisulphite and ammonia.
    (ii) The penta-acetate of glucose does not react with hydroxylamine indicating absence of —CHO group.
    (iii) Mutarotation: When glucose is crystallized from a concentrated solution at 30°C, it gives a form of glucose m.p. 146°C, [α]D = (+) 111°, on the other hand the β-form (m.p. 15°C), [α]D = (+) 19.2° is obtained on crystallization of glucose from a hot saturated aqueous solution at a temperature above 98°C. This behaviour cannot be explained by its open chain structure.

    Question 121
    CBSEENCH12009581

    What are essential and non-essential amino acid? Give two examples of each type.

    Solution

    Essential amino acids : Those amino acids which are not synthesised by our body are called essential amino acids. They must be part of our diet. Their deficiency leads to diseases such as Kwashiorkor (water balance in the body is disturbed). Valine, leucine, isoleucine, phenyl alanine, methionine, tryptophan, threonine, lyslne, arginine and histadine are ten essential amino acids.
    Non-essential amino acids: The amino acids, which can be synthesised in the body, are known as non-essential amino acid. They are also called dispersable amino acids e.g., glycine, alanine, seriqe, cysteine, glutamine, tyrosine, proline, aspartic acid, asparagine, glutamic acid.

     

    Question 122
    CBSEENCH12009582

    Define the following as related to proteins:
    (i) Peptide linkage     (ii) Primary structure    (iii) Denaturation. 

    Solution

    i) Peptide linkage: In peptide linkage amide formed between -COOH groups of one molecule of an amino acid and -NH2 group of another molecule of the amino acid by the elimination of a water molecules.


    (ii) Primary structure:The primary structure of protein refers to the specific sequence in which various amino acids are present in it, i.e., the sequence of linkages between amino acids in a polypeptide chain. The sequence in which amino acids are arranged is different in each protein. A change in the sequence creates a different protein.

    (iii) In a biological system, a protein is found to have a unique 3-dimensional structure and a unique biological activity. In such a situation, the protein is called native protein. However, when the native protein is subjected to physical changes such as change in temperature or chemical changes such as change in pH, its H-bonds are disturbed. This disturbance unfolds the globules and uncoils the helix. As a result, the protein loses its biological activity. This loss of biological activity by the protein is called denaturation.
    During denaturation, the secondary and the tertiary structures of the protein get destroyed, but the primary structure remains unaltered. One of the examples of denaturation of proteins is the coagulation of egg white when an egg is boiled.
    Question 123
    CBSEENCH12009583

    What are the common types of secondary structure of proteins?

    Solution
    Secondary structure of protein: The secondary structure of protein refers to the shape in which a long polypeptide chain exist. They are found exist in two different types of structures viz.α-helix and β-pleated sheet structure. It arises due to the regular folding of the backbone of the polypeptide chain due to intermolecular hydrogen bonding between the carboxyl and amino group. In an α-helix, the peptide chain coils and the turns of the coil are held together by hydrogen bonds. In contrast to this, another type of secondary structure is possible in which the protein chains are stretched out and is known as β-structures.
    Question 124
    CBSEENCH12009584

    Differentiate between globular and fibrous proteins. 

    Solution

    Difference between globular protein and fibrous protein:

    Fibrous protein

    Globular protein

     

    1.It is a fibre-like structure formed by the

    polypeptide chain. These proteins are held

    together by strong hydrogen and disulphide

    bonds

    1.

    The polypeptide chain in this

    protein is folded around itself,

    giving rise to a spherical

    Structure.

     

    2. It is usually insoluble in water, but soluble in strong acids and bases.

    2. It is usually soluble in water, acids, bases and salts.

     

    3. They have comparatively stronger intermolecular forces of attraction.

    3. They have weak intermolecular hydrogen bonding.

    4. Example: Collagen, fibroin, myosin, hair, skin,silk, wool, etc.

    4. Egg, albumin, casein of milk, insulin.

    Question 125
    CBSEENCH12009585

    How do you explain the amphoteric behaviour of amino acids?

    Solution

     

    In aqueous solution, the carboxyl group of an amino acid can lose a proton and the amino group can accept a proton to give a dipolar ion known as zwitter ion.
    Therefore, in zwitter ionic form, the amino acid can act both as an acid and as a base. Thus, amino acids show amphoteric behaviour.

    Question 126
    CBSEENCH12009586

    What is the effect of denaturation on the structure of proteins?

    Solution

    Denaturation of proteins: Proteins are very sensitive to the action of heat, change of pH, presence of electrolytes and radiations (particularly of short wavelength). Whenever proteins are subjected to such changes in the surroundings, they undergo some structural changes leading to disruption of three dimensional structure. This causes permanent loss of activity to proteins. Disruption of the native conformation of protein, by changing its environment, resulting in loss of its biological activity, is known as denaturation of proteins.

    Question 127
    CBSEENCH12009587

    How are vitamins classified? Name the vitamin responsible for the coagulation of blood.

    Solution

    Vitamins are classified into two groups depending upon their solubility in water or fat.
    i) Fat soluble vitamins: Vitamins which are soluble in fat and oils but insoluble in water. These are Vitamins A, D, E, and K.
    ii) Water soluble vitamins: Vitamins which are soluble in water. These are B group vitamin and vitamin C.
    Vitamin K is responsible for the coagulation of blood.

    Question 128
    CBSEENCH12009588

    Why are vitamin A and vitamin C essential to us? Give their important sources.

    Solution

    (i) The chemical name of vitamin A is retinol.
    The deficiency of vitamin A leads to xerophthalmia and night blindness. Important Sources of Vitamin ‘A’ : Milk, butter, egg, fish, and fish oil (Cod liver oil). It can also be synthesised in the body from carotenoids present in carrots, tomatoes, ripe mangoes etc. Carotenoids are the precursors of vitamin A.
    (ii) The chemical name of vitamin C is ascorbic acid. The deficiency of vitamin C leads to scurvy.
    Important Sources of Vitamin C: Citrus fruits (oranges, lemon, grape fruit, lime etc.), amla, cabbage, guava etc.

     

    Question 129
    CBSEENCH12009589

    What are nucleic acids? Mention their two important functions.

    Solution

    Nucleic acids are biomolecules found in the nuclei of all living cells, as one of the constituents of chromosomes. Nucleic acids composed of a phosphoric acid group, a carbohydrates, and two purines and pyrimidines.There are mainly two types of nucleic acids − deoxyribonucleic acid (DNA) and ribonucleic acid (RNA). Nucleic acids are also known as polynucleotides as they are long-chain polymers of nucleotides.
    Fuctions:
    (i) DNA is responsible for the transmission of inherent characters from one generation to the next. This process of transmission is called heredity.
    (ii) Nucleic acids (both DNA and RNA) are responsible for protein synthesis in a cell. Even though the proteins are actually synthesised by the various RNA molecules in a cell, the message for the synthesis of a particular protein is present in DNA

    Question 130
    CBSEENCH12009590

    What is the difference between a nucleoside and a nucleotide?

    Solution

    Nucleosides:
    1. It contains only two basic components of nucleic acids, i.e., a pentose sugar and a nitrogenous base.
    2. During their formation, 1-position of the pyrimi-dine or 9-position of the purine is linked to C, of the sugar (ribose or deoxyribose) by a β-linkage.

    Nucleotides:
    1. It contains all the three basic components of nucleic acids, i.e., a phosphoric acid group, a pentose sugar and a nitrogenous base.
    2. These are formed by esterification of one of the hydroxyl groups (usually C5—OH of the sugar part) of the nucleoside with phosphoric acid.

    Question 131
    CBSEENCH12009591

    The two strands in DNA are not identical but are complimentary. Explain.

    Solution

    (i) DNA has double helical structure in which two strands are twisted about each other held in position by H-bonds between the bases.
    (ii) The two bases guanine and cytosine are complementary bases of DNA. Similarly, adenine and thymine are also complementary bases of DNA.
    iii) If one of these bases is located on one chain of DNA, its complementary base is hydrogen bonded to it on the other chain. This means that the guanine base present on one chain of DNA is hydrogen bonded to its complementary base, cytosine present on the other chain. Similarly, adenine is hydrogen bonded to thymine on the other chain.

    Question 132
    CBSEENCH12009592

    The two strands in DNA are not identical but are complimentary. Explain.

    Solution

    (i) DNA has double helical structure in which two strands are twisted about each other held in position by H-bonds between the bases.
    (ii) The two bases guanine and cytosine are complementary bases of DNA. Similarly, adenine and thymine are also complementary bases of DNA.
    If one of these bases is located on one chain of DNA, its complementary base is hydrogen bonded to it on the other chain.
    This means that the guanine base present on one chain of DNA is hydrogen bonded to its complementary base, cytosine present on the other chain. Similarly, adenine is hydrogen bonded to thymine on the other chain.

    Question 133
    CBSEENCH12009593

    Write the important structural and functional differences between DNA and RNA.

    Solution

    DNA RNA
    1.DNA exists as double helix. 1. RNA exists-as single chain.
    2. It is high polymer containing 2500 to 5000 nucleotides. 2. It is relatively smaller polymer containing 75 to 1200 nucleotides.
    3.In DNA. the sugar is deoxyribose. 3.In RNA the sugar unit is ribose.
    4. The base units in DNA are adenine, guanine, cytosine and thymine. 4. The base units in RNA are adenine, guanine, cytosine and uracil.
    5.Uracil is absent in DNA. 5. Thymine is absent in RNA.
    6. The hydrolysis products of DNA are phosphoric acid, deoxyribose, the bases A, G, C and T.

    6.    The hydrolysis products of RNA are phosphoric acid, ribose and bases A.G, C and U.

     
    Question 134
    CBSEENCH12009594

    Compare α-D glucose with β-D glucose.

    Solution
    α-D glucose β-D glucose
    1.It is prepared by crystallization from cold aqueous solution. 1.It is prepared by crystallisation from hot saturated aqueous solution.
    2.It melts at 419 K. 2.It melts at 421 -423 K
    3. Specific rotation of freshly prepared aqueous solution is 113°. 3.Specific roation of freshly prepared aqueous solution is 19°.
    Question 135
    CBSEENCH12009595

    State significance of primary and secondary structures of proteins.

    Solution

    The sequence in which the amino acids are arranged in a protein is called the primary structure of protein. The primary structure of protein determines its function and is critical to its biological activity. The change of just one amino acid in the sequence can alter its biological activity.
    Secondary structure of proteins refers to the arrangement of polypeptide chains which arises as a result of hydrogen bonding. It arises due to regular folding of the back bone of polypeptide chain. It is two types.
    (a) α-helix-Globular protein have α-helix structure.
    (b) β-pleated-fibrous proteins have α-pleated structure.

    Question 136
    CBSEENCH12009596

    What are the different types of RNA found in the cells of organisms? State the functions of each type.

    Solution

    There are three types of RNA found in the cells:
    (i) Messenger RNA (mRNA): It provides a template for assembling amino acids in polypeptide chains. It carries the information transmitted from DNA.
    (ii) Transfer RNA (tRNA): It carries the amino acids to mRNA template and also helps the mRNA to recognise the amino acids. Thus, tRNA molecules serve both as carrier of amino acids and interpreter of genetic code.
    (iii) Ribosomal RNA (rRNA): It is an integral part of ribosomes that also takes part in protein synthesis. About 75% of cellular component of RNA is r-RNA.

    Question 137
    CBSEENCH12009597

    What are nucleic acids? Explain their functions in the synthesis of proteins.

    Solution

    Nucleic acids are biomolecules found in the nuclei of all living cells, as one of the constituents of chromosomes.Nucleic acids are consist of a sugar unit, a phosphate group and a nitrogen base unit. These contain two type of bases:
    (i) Pyrimidine bases.
    (ii) Purine bases.
    These are two types of sugar units in nucleic acids:
    (i) Ribose.
    (ii) Deoxyribose.
    Nucleic acids are also known as polynucleotides as they are long-chain polymers of nucleotides.
    Depending upon the type of sugar unit, there are two types of nucleic acids:
    deoxyribonucleic acid (DNA) and ribonucleic acid (RNA). 
    Two main functions of nucleic acids are:
    (i) DNA is responsible for the transmission of inherent characters from one generation to
    the next. This process of transmission is called heredity.
    (ii) Nucleic acids (both DNA and RNA) are responsible for protein synthesis in a cell.
    Even though the proteins are actually synthesised by the various RNA molecules in a
    cell, the message for the synthesis of a particular protein is present in DNA.


    Question 138
    CBSEENCH12009598

    Name the deficiency diseases caused due to lack of the vitamin A, C, E, B1, B12 B6and K. 

    Solution
    Name of Vitamin Deficiency disease
    Vitamin A Xerophthalmia i.e., hardening of cornea of eye.
    Vitamin C Scurvy
    Vitamin E Sterility
    Vitamin B1 Beri-beri (a disease of nervous system)
    Vitamin B12 Pemicious Anaemia
    Vitamin B6 Bevere dermatitis, convulsions.
    Vitamin K Hemorrhagic conditions.
    Question 139
    CBSEENCH12009599

    State differences between α-helix and β-pleated sheet structure.

    Solution
    α-helix structure β-pleated structure
    1. In α-helix. the peptide chains are coiled upto form helix which is right handed involving hydrogen bonding. 1.The peptide chains lie side by side held together by inter molecular hydrogen bonding.
    2. Myosin, keratin and wool have α-helix structure. It acquires coil shape.

    2. Silk has β-pleated structure. It acquires streched sheet structure.

     
    Question 140
    CBSEENCH12009600

    State differences between primary and secondary structure of a protein.

    Solution

    Primary structure

    Secondary structure

    1. The sequence in which amino acids are arranged in a protein is called primary structure. It involves covalent bond.

     

    1. The polypeptide chain gets folded due to intermolecular hydrogen bonding forming α-helix and β-pleated structure having polypeptide chains lie side by side involving inter molecular hydrogen bonding.

    Question 141
    CBSEENCH12009601

    State difference between Enzymes and Co-enzymes.

    Solution
    Enzymes Co-enzymes
    1. They are biological catalysts which are required to catalyse biochemical reaction, e.g. amylase,streptokinase, maltose. 1. They are non- proteinous part which increase the activity of enzymes e.g., metal ion like, Mg2+, Zn2+, Mn2+, Na+, K+ or small molecules are called co-enzymes. 
    2. All enzymes are proteins. 2. Co-enzymes are non-proteinous.
    Question 142
    CBSEENCH12009602

    Name the bases present in RNA molecule. 

    Solution
    Adenine, Guanine, Cytosine, Uracil.
    Question 143
    CBSEENCH12009603

    Name the water insoluble fraction of starch. Name the monomer of this ?

    Solution

    Amylopectin is a water insoluble fraction of starch.It is a polymer of alpha-glucose.

     
    Question 144
    CBSEENCH12009604

    What do you mean understand by tertiary structure of proteins? Mention the forces involved informing these structures.

    Solution

    Tertiary structure of proteins : When the polypeptide chain with its secondary structure is further folded and twisted about itself a tertiary structure is formed. The tertiary structure of a protein adopts coiled compact structure of varying size and shape. The various forces involved in forming tertiary structures are,
    (i)    Hydrogen bonding.
    (ii)   Disulphide bridge.
    (iii)   Ionic or salt bridge.
    (iv)   Hydrophobic interaction.

    Question 145
    CBSEENCH12009605

    Mention two structural differences between amylopectin and cellulose.

    Solution

    Amylopectin

    Cellulose

    1. It has a branched chain structure.

    1. It is a linear polymer.

    2. It is made of α-glucose units.

    2. It is made of β-glucose units.

    Question 146
    CBSEENCH12009606

    Name the product obtained on complete hydrolysis of DNA. Enumerate the structural differences between DNA and RNA. In what way is a nucleotide different from a nucleoside? Illustrate with examples.

    Solution

    The products of complete hydrolysis of DNA are:
    (i) a pentose sugar
    (ii) two types of heterocyclic nitrogenous bases.
    (iii) phosphoric acid
    The structural differences between DNA and RNA are:
    (i) DNA has deoxyribose while RNA has ribose sugar.
    (ii) DNA contains thymine and RNA has uracil.
    (iii) DNA is double stranded while RNA is single stranded.
    Nucleosides: The N-glycosides of purine or pyrimidine bases with pentose sugars are known as nucleosides.
    Nitrogen space Base plus space Sugar space space space rightwards arrow space space Nucleoside
    Nucleotides: A nucleotide is a phosphate ester of nucleoside and consists of a purine or pyrimidine base, the 5-carbon sugar and one or more phosphate groups.
    Nitrogen Base + Sugar + Phosphate = Nucleotide

    Question 147
    CBSEENCH12009607

    What are nucleic acids? Explain their role in replication.

    Solution

    Nucleic acids are biomolecules which are present in the nucleus of living cells. There are two types of nucleic acids namely DNA (deoxyribo nucleic acid) and RNA (ribonucleic acid). The nucleic acids direct the synthesis of protein and are responsible for genetic information.
    The process by which identical DNA molecules are synthesized from DNA molecules is called replication. As the cell divides the two strands of DNA are produced zip by zip from the double helix. These strands act as templates for the synthesis of new strands. The new strand is complementary to its parent strand. Now, the parent strand joins the new complementary strand and a double stranded helix of a new DNA is formed which is a true copy (replica) of the mother DNA. The second parent DNA strand also forms a new DNA with its complementary new DNA strand. In this way, two identical DNA molecules are formed from one DNA molecule.

    Question 148
    CBSEENCH12009608

    Describe four functions of carbohydrates in living organism.

    Solution

    Functions of carbohydrates:
    1. They support the plant structure, e.g., cellulose.
    2. They produce energy necessary for functioning of living body and doing work.
    3. They are used to store chemical energy in form of glycogen in liver. In case of emergency like fasting or illness, glycogen hydrolyses to glucose and thus supplies the necessary energy. Starch is main storage polysaccharide of plants.
    4.Cellulose present in grass and plants act as a food for various grazing animals. These animals contain specific enzymes which can hydrolyse cellulose.

    Question 149
    CBSEENCH12009609

    The tertiary structure of many proteins dissolved in water is disrupted by heating above 80°C, but primary structure is unaffected. Explain.

    Solution

    In the primary structure of proteins, the amino acid units are joined together by strong covalent bonds in a linear polymeric form. However, in the tertiary structure of proteins, the individual polypeptide chains are extensively coiled into globular like structure, with hydrogen bonds between carboxyl and amino acids.
    When a protein dissolved in water is heated above 80°C rearrangement of secondary and tertiary structures occurs, since heat can cause disruption of these comparatively weaker forces of attraction. However, the primary structure is not affected, since it involves comparatively much stronger covalent bonds between various amino acid units.

    Question 150
    CBSEENCH12009610
    Question 151
    CBSEENCH12009611

    How are glucose molecules joined together to make starch, glycogen and cellulose?

    Solution

    (i) Starch: Starch is a polymer of α-glucose and consists of two components, namely, amylose and amylopectin. Amylose is a linear polymer of α-D-glucose. It contains about 200 glucose units which are linked to one another through α-linkage involving C1 of one glucose unit with C4 of the other. Amylopectin, on the other hand, is a highly branched polymer.
    (ii) Glycogen: It is a polymer of about thousand glucose units arranged in the form of highly branched chain.
    (iii) Cellulose: Cellulose is a linear polymer of β-D-glycose in which C1 of one glucose unit is connected to C4 of the other as shown below

    Question 152
    CBSEENCH12009612

    What are reducing and non-reducing sugars? What is the structural feature characterizing reducing sugars ?

    Solution

    Those carbohydrates which contain free aldehyde or ketonic group reduce Fehling’s solutions and Tollen’s reagent are called reducing sugar e.g., monosaccharides like glucose, fructose, galactose are reducing sugars.
    Those carbohydrates which do not contain free aldehydes or ketonic group and do not reduce Fehling’s solution and Tollen’s reagent are called non-reducing sugars, e.g., maltose, lactose, sucrose.

    Question 153
    CBSEENCH12009613

    Write the following about protein synthesis:
    Name the location where protein synthesis occurs.

    Solution
    Protein synthesis takes place at the ribosome in the cytoplasm.
    Question 154
    CBSEENCH12009614

    Write the following about protein synthesis:
    How do 64 codons code for only 20 amino acids?

    Solution
    proteins is the sequence of four different nucleotides that is used to convey information for combination of 20 amino acids to form polypeptide chain. Each amino acid is represented by three nucleotides (triplet). This is true. There are only 16 different doublets of four nucleotides (42) and that 64 (43) triplets. These are 64 amino acids. It means that more than one codon can code for same amino acids.
    Question 155
    CBSEENCH12009615

    Write the following about protein synthesis:
    Which of the two bases of the codon are most important for coding?

    Solution
    First two bases of codon are most important for coding.
    Question 156
    CBSEENCH12009616

    What deficiency diseases are caused due to lack of vitamins A, B, B6 and K in human diet?

    Solution

    Following are the deficiency diseases are caused:
    i) Xerophthalmia or night-blindness is deficiency diseases of vitamin A.
    ii) Beri-Beri is deficiency disease of vitamin B.
    iii) Nervous disturbance (convulsion), severe dermatitis is caused by deficiency of vitamin B6.
    iv) Haemophilia is caused by deficiency of vitamin K.

    Question 157
    CBSEENCH12009617

    Draw open chain structure of aidopentose and aldohexose. How many asymmetric carbons are present in each?

    Solution

    Aidopentose has three asymmetric carbon atoms whereas aldohexose has four asymmetric carbon atoms.
    Question 158
    CBSEENCH12009618

    Draw simple Fisher projections of D-and L-glucose. Are these enantiomers?

    Solution
    The Fisher projections of D and L glucose are shown below:

    These are enantiomers.
    Question 159
    CBSEENCH12009619
    Question 161
    CBSEENCH12009621

    Which forces are responsible for the stability of α-helix? Why is it named as 3.6 helix?

    Solution

    The stability of alpha –helix structure is due to intramolecular of H-bonding between –NH- and –CO- groups of the same polypeptide chain. The alpha-helix is termed as 3.613 helix as each turn of the helix has nearly 3.6 amino acids and the hydrogen bonding leads to the formation of a 13-membered ring.

    Question 162
    CBSEENCH12009622

    Answer the following queries about proteins:
    How are proteins related to amino acids?

    Solution
    Proteins are biopolymers of amino acids.
    Question 163
    CBSEENCH12009623

    Answer the following query about proteins:
    How are oligopeptides different from polypeptides?

    Solution
    Oligopeptides on hydrolysis give 3 to 12α-amino acids whereas polypeptides give a large number of α-amino acids.
    Question 164
    CBSEENCH12009624

    Answer the following query about proteins:
    When is a protein said to be denatured?

    Solution
    When a tertiary protein loses its biological activity due changing pH or heating is said to be denatured.
    Question 165
    CBSEENCH12009625

    What is mutation? What are the consequences of mutation?

    Solution

    Any change in the base sequence of DNA which leads to the synthesis of proteins with altered amino acid sequence is called mutation.
    Consequence of mutations: Mutation leads to the synthesis of proteins with an altered amino acid sequence. The proteins with changed sequences of amino acids may have no biological activity leading to the death of a cell.The defective gene may also cause abnormality or certain genetic diseases.

     
    Question 166
    CBSEENCH12009626

    Explain the role of RNA in protein synthesis in a cell.

    Solution
    Protein synthesis takes place in the cytoplasm and for this various types of RNA molecules are involved in it. Protein synthesis is a fast process; and about 20 amino acids are added in one second. During protein synthesis, amino acids are linked together by covalent bonds between the carbonyl groups of one and the amino group of next amino acid. In this way a polypeptide chain is formed; and a protein may be formed of many polypeptide chains.
    Question 167
    CBSEENCH12009627

    Describe briefly the following:
    (i) Transcription   (ii) Translation.

    Solution

    The genetic information coded in DNA in the form of specific base sequence has to be translated and expressed in the form of synthesis of specific proteins, which perform various functions in the cell. This is brought about in two steps called transcription and translation.
    The transcription involves copying of DNA sequence into a complimentary RNA molecule called messenger RNA (m-RNA). The copying principle as in replication, but with the difference that the base A pairs with U in RNA.
    During translation m-RNA directs protein synthesis in the cytoplasm of cell with the involvement of another type of RNA molecule called, transfer RNA (t-RNA) and the ribosomal particles.

    Question 168
    CBSEENCH12009628

    What reaction is involved in the formation of disaccharides from monosaccharides ? Give the chemical reaction.

    Solution
    The formation of disaccharides from monosaccharides involves the conversion of hemiacetal to acetal. In this two molecules of α-glucose take part.


    Question 169
    CBSEENCH12009629

    Define the following terms: (i) Gene, (ii) Genetic code, (iii) Transcription, (iv) Translation, (v) Codon.

    Solution

    (i) Gene: Gene is a micelle protein which is considered to the unit of heredity.
    (ii) Genetic Code: The heredity message stored in the arrangement of bases in the DNA molecules is called the genetic code.
    (iii) Transcription: The way the code on DNA is copied to give the complimentary code on RNA is called transcription.
    (iv) Translation: The way the four base code in nuclei acids is turned into a 20 unit code needed to specify the amino acid sequence in protein during synthesis is called translation.
    (v) Codon: The three base sequence on a mRNA molecule that specifies the amino acids in a protein is called a codon.

    Question 170
    CBSEENCH12009630

    List three functions of the nucleotides in a cell.

    Solution

    Function of nucleotides:
    (i) Nucleotides are the monomer units of nucleic acids.
    (ii) Some of the nucleotides act as coenzymes.
    (iii) Each codon is made up of three nucleotides, hence they are helpful in the synthesis of any specific protein.

    Question 171
    CBSEENCH12009631

    What is the effect of pH on the activity of enzymes?

    Solution

    Enzymes are highly sensitive to a change of pH value. Since enzymes are proteins, pH change greatly affect the ionic character of amino and carboxylic acid groups on the protein surface. This change affects the catalytic nature of an enzyme also. The enzymes function within a narrow range of pH value. For example,
    Enzyme Pepsin Ptyalin Trypsin pH range 1.8 to 2.2 5.6. to 6.6 7.5. to 8.3
    The low or high pH value can cause considerable denaturation of the protein and hence makes enzyme protein inactive.

    Question 172
    CBSEENCH12009632

    The two samples of DNA, A and B have melting temperatures  340 and 350K respectively. Draw conclusion from this data regarding their base content.

    Solution
    The B sample of DNA having higher melting point must be having more GC content as compared to sample A. Since GC base pair having 3 hydrogen bonds as compared to AT base pair having only 2 hydrogen bonds, results in stronger bonding.
    Question 173
    CBSEENCH12009633

    What are polysaccharides? Name one of them. How is it important to us?

    Solution

    Polysaccharides are carbohydrates which on hydrolysis gives hundreds or even thousands of monosaccharides units. Cellulose is an example of polysaccharide.
    Cellulose is an example of polysaccharide. Cellulose is important to us in the following ways:
    (i) It is used in the manufacture of rayon and gun cotton (explosive).
    (ii) It is used in the manufacture of cellotape and cellophone paper.
    (iii) It is used in the manufacture of nitrocellulose (used as rocket propellant).

    Question 174
    CBSEENCH12009634

    Give any two reactions of glucose to show the presence of an aldehyde group.

    Solution
    (i) Glucose reacts with hydroxylamine to form glucose oxime

     Glucose reacts with hydrogen cyanide to form cyanohydrin.


    These reaction confirm the presence of a carbonyl group (>C=O) in glucose.
    ii) Glucose gets oxidised to six carbon carboxylic acid (gluconic acid) on reaction with a mild oxidising agent like bromine water. This indicates that the carbonyl group is present as an aldehydic group.

     
    Question 175
    CBSEENCH12009635

    How will you show the presence of,
    (i) primary alcoholic group.
    (ii) Six carbon atoms in a straight chain in glucose.

    Solution
    (i) On oxidation with HNO3 glucose yields a dicarboxylic acid, saccharic acid. This indicates the presence of a primary alcoholic (-OH) group in glucose.


    (ii) Reduction with HI on prolonged heating, glucose yields n-hexane which proves that all six carbon atoms are in a straight chain.

    Question 176
    CBSEENCH12009636

    A tipeptide on complete hydrolysis give glycine, alanine and phenyl alanine. Using three letter symbols, write down the possible sequences of the tripeptide.

    Solution

    A tripeptide is a peptide obtained by the condensation of three amino acids. The possible combinations of tripeptide obtained from glycine, alanine and phenylalanine are:
    (i) Gly-Ala-Phe
    (ii) Gly-Phe-Ala
    (iii) Ala-Gly-Phe
    (iv) Ala-Phe-Gly
    (v) Phe-Ala-Gly
    (vi) Phe-Gly-Ala.

    Question 177
    CBSEENCH12009637

    If two amino acids: alanine and phenyl alanine react together, how many possible dipeptides can be formed? Write down the structures and names of each one. Also, write their names using three and one letter abbreviation for each amino acids.

    Solution

    Its name is alanyl phenylalanine. Its three letter name is Ala-Phe and using one letter abbreviation, its name is A—F.

    Name: Phenylalanine
    Three letter name is Phe -Ala one letter abbreviation is F—A.

    Question 178
    CBSEENCH12009638

    Which bonds in the backbone of a peptide can rotate freely and which cannot? Give reasons.

    Solution
    The rotation is not allowed in the peptide bond. The free rotation of a peptide chain can only occur around the bonds joining the nearly planar amide groups to the α-carbons. The free rotation about the peptide bond is respected due to the partial double bond character of the C—N bond in peptide linkage. Therefore, —CONH—group is planar and rigid.

    Question 179
    CBSEENCH12009639

    Name the purine and pyrimidine bases present in DNA and RNA. Give the structure of any one of the pyrimidine base.

    Solution
     

    DNA

    RNA

    Purine Bases

    Pyrimidine Bases

    Adenine (A)
    Guanine (G)

    Thymine (T)
    Cytosine (C)

    Adenine (A)
    Guanine (G)

    Uracil (U)
    Cytosine (C)

    Structure of Uracil (pyrimidine base)

    Question 180
    CBSEENCH12009640

    State the important features of the genetic code.

    Solution

    The genetic code has the following important features:
    (i) It is universal.
    (ii) It degenerates, i.e., more than one codon code for an amino acids.
    (iii) It is commaless.
    (iv) The third base of the codon is less specific.

    Question 181
    CBSEENCH12009641

    Which vitamin is called ascorbic acid? What are its physiological functions? Which disease is caused by the deficiency of this vitamin?

    Solution

    Vitamin C is called ascorbic acid. Its physiological functions are:
    (i) It improves appetite.
    (ii) It helps in curing cold.
    (iii) It helps in the healing of wounds and cuts.
    (iv) It helps in the growth of good teeth.
    The deficiency of this vitamin causes a disease called scurvy. This causes swelling and bleeding of gums, as well as pains in muscles and joints.

    Question 182
    CBSEENCH12009642

    What do you understand by a vitaminoses? Name the defeiciency disease caused due to lack of Vitamin A and K.

    Solution

    A vitaminoses is defined as the condition of vitamin deficiency. A lack of one or more vitamins leads to characteristic deficiency symptoms in man. Multiple deficiencies are caused by the lack of more than one vitamin.
    The deficiency disease caused by lack of vitamin A is night blindness, and retarded growth. The deficiency disease caused by lack of vitamin K is increased time of blood clottings and hemorrhagic condition.

    Question 183
    CBSEENCH12009643

    Explain the following:
    Glucose responds Fehling solution and osazone, it does not react with Schiff’s base and sodium bisulphite.

    Solution
    Fehling and osazone reactions are irreversible and hence the equilibrium is shifted to restore the low concentration (0.02%) of open chain aldehydic form with the result glucose reacts with these reagents. On the other hand the Schiff and bisulphite reactions are reversible and hence the equilibrium of such reactions favours unreacted hemiacetal.
    Question 184
    CBSEENCH12009644

    Explain the following:
    Glucosides react neither with Fehling solution nor with Tollen's reagent. They also do not allow mutarotation.

    Solution
    Glucoside are stable in aqueous solution used in mutarotation and also in the basic Fehling’s and Tollen's solution. Hence open chain aldehydic form is not produced.
    Question 185
    CBSEENCH12009645

    Explain the following:
    Although fructose does not have an aldehydic group, it reacts with Fehling solution.

    Solution
    Fehling solution is prepared in presence of base. Now since fructose isomerises to glucose in presence of base of Fehling solution, it also reacts with Fehling solution.
    Question 186
    CBSEENCH12009646

    What is melting temperature (Tm) of DNA? A DNA molecule with more number of GC base pairs than AT base pairs has higher Tm than the one with lesser number of GC base pairs than AT base pairs. Explain why?

    Solution

    The temperature at which two strands of DNA separates completely is known as its melting temperature. It is specific for each specific sequence.
    A DNA molecule with more number of GC base pairs than AT base pair has higher melting temperature because each GC pair contains three hydrogen bonds, while each AT base pair contains two hydrogen bonds.Therefore, more number of hydrogen bonds are present in DNA molecule with more GC pairs than AT pair.

    Question 187
    CBSEENCH12009647

    What are forces holds the two strands of DNA together in a double-helix structure? Draw structure to show the bonding between adenine and thymine, and between guanine and cytosine.

    Solution

    Hydrogen bonding holds the two strands of DNA together in a double-helix structure.
    ‘A’ pairs up with ‘T’ via two hydrogen bonds while G pairs up with C via three hydrogen bonds.

    Question 188
    CBSEENCH12009648

    'DNA replication is semi-conservative'. Explain.

    Solution
    Replication of DNA involves the unwinding of the double-helix structure. Each single strand then acts as a template for the synthesis of a new DNA molecule again with a specific base pairing. During this replication, only half of the parental DNA is conserved and only one strand is synthesised. That’s why DNA replication is semiconservative.
    Question 189
    CBSEENCH12009649

    What is transcription with reference to protein synthesis? How does it take place?

    Solution

    Transcription means copying the sequence of bases from DNA on messenger RNA (m-RNA). The copying of DNA sequence into m-RNA proceeds according to the same base pairing principle as in replication but differ in the following two respects:
    (i) During m-RNA synthesis, the DNA double helix structure opens up and the ribonucleotides assemble along the uncoiled strand of DNA.
    (ii) The base adenine (A) in DNA strand pair up with the uracil (U) in RNA.
    After transcription, the m-RNA-DNA double helix separates. The m-RNA detaches itself and migrates to cytoplasm, while the DNA returns to its double helix structure.

    Question 190
    CBSEENCH12009650

    What happens when D-glucose is treated with following reagents?
    (i) Acetic anhydride                  
    (ii) Hydroxylamine
    (iii) Tollen’s reagents              
    (iv) Fehling solution
    (v) Phenyl hydrazine.

    Solution
    (i) Acetylation of glucose with acetic anhydride gives glucose petnaacetate which confirms the presence of five -OH groups.

    (ii) Glucose reacts with hydroxylamine to give monoxime. This reaction confirms the presence of a carbonyl group.

    (iii) Glucose reduce ammonical silver nitrate (Tollen’s reagent) to metallic silver.

    (iv) Glucose reduces Fehling’s solution and gives brick red precipitate due to formation of cuprous oxide (Cu2O):

    (v) D-glucose reacts with phenylhydrazine to give glucose phenylhydrazone which is soluble in water. If excess of phenylhydrazine is used, dihydrazone, known as glucosazone is formed.
    Question 191
    CBSEENCH12009651

    Define enzymes. How do enzymes differ from ordinary chemical catalysts? Comment on the specificity of enzyme action. What is the most important reason for their specificity? Explain the mechanism of enzyme catalysis.

    Solution

    Enzymes are biocatalyst produced by the living cells which catalyse many biochemical reactions in animals and plant bodies. Enzymes are protein substances.
    Enzymes differ from ordinary chemical catalysts in the following ways:
    (i)    Enzyme catalyst the reaction by about million times faster than the normal chemical catalysts.
    (ii)    Enzymes are very specific in their action. Each biochemical reaction requires a particular enzyme for it.
    (iii)    Enzymes work under milk conditions of temperature and at specific pH.
    Specificity of enzyme action : Enzymes are extremely specific; Each reaction is generally catalyzed by a particular enzyme. For example, hydrolysis of urea is catalysed by only urease and none of the several thousand other enzymes present in the cell catalyse this reaction.
    NH subscript 2 CONH subscript 2 plus straight H subscript 2 straight O space rightwards arrow with urease on top space 2 NH subscript 3 plus 2 CO subscript 2
    The specificity of enzymes results from the fact that each enzyme has a specific active site one its surface. When the reactant molecules, called the substrates of the reaction bind at the active site, a chemical change is initiated. In most of the cases, substrates bind to the active site through inter-molecular forces like H-bonds, dipole forces and other weak attraction.
    Mechanism of enzymatic reaction involves four stages:
    (i) The formation of complex between enzyme and substrate.
    straight E plus straight S space rightwards arrow ES
    (ii) The conversion of this complex to an enzyme-intermediate complex
    ES space rightwards arrow space EI
    (iii) Further conversion of El to a complex between enzyme and product (EP)
    EI space rightwards arrow space EP
    (iv) The dissociation of the enzyme-product, leaving the enzyme unchanged

    Question 192
    CBSEENCH12009652

    What are the building blocks (repeat units) of proteins? Describe the structure of protein.

    Solution

    A protein is a high polymer on hydrolysis it yields amino acids. Thus, amino acids are the monomeric units of all proteins. In a molecule of protein, the amino acid residues are joined by peptide bonds. Therefore, proteins are also called condensation products of amino acids or polyamide.
    Structure of proteins: (a) Primary structure: Primary structure is the combination of amino acids in a proper sequence through peptide bonds.

    (b) Secondary structure: In many proteins, polypeptide chain gets coiled up to form α-helix which is right handed and is called α-helix. In the helix each NH group is hydrogen bonded to the carbonyl oxygen of the third amino acids residue from it. It is this hydrogen bonding between different parts of the same chain which holds the helix together. Some proteins have β-pleated structure. This is also called β-sheet structure. In the sheet arrangement two peptide chains lie side by side and are joined via hydrogen bonds.


    Fig. (a) Helical structure (b) The peptide
    backbone in a helical structure.


    Fig. β-pleated sheet structure of a protein
    (c)    Tertiary structure: The peptide chains with its secondary may be further folded and twisted about itself forming many structural coils of diverse sizes or shapes. They, brings some distant amino acids residues close to each other. Tertiary structures are held and stabilized by : (i) hydrophobic interactions, (ii) hydrogen bonds, (iii) Van der Waals forces and (iv) disulphide linkages between two side chains.
    (d) Quaternary structure: This defines the degree of polymerization of protein unit. Both fibrous and globular proteins may contain one or more polypeptide chains. In case of fibrous protein these are called monomeric while in case of globular these are referred to as oligomeric. The individual peptide chains of an oligomeric protein are called promoters. These promoters may be same or different but are held together by weak binding force.

    Question 193
    CBSEENCH12009653

    What do you mean by Zwitter ions and isoelectric points of amino acids?

    Solution
    Amino acid contains —NH2 group (basic) and —COOH group (acidic). These two groups can interact and neutralize each other. Carboxyl group loses a proton and amino group accepts this proton to convert amino acid into Zwitter ion or dipolar ion.

    Question 194
    CBSEENCH12009654
    Question 196
    CBSEENCH12009656
    Question 197
    CBSEENCH12009657
    Question 198
    CBSEENCH12009658

    The chemical name of vitamin C is _________.

    Solution
    ascorbic acid
    Question 199
    CBSEENCH12009659
    Question 200
    CBSEENCH12009660

    An example of disaccharide is __________.

    Solution
    sucrose
    Question 201
    CBSEENCH12009661

    RNA and DNA are collectively known as _________.

    Solution
    nucleic acids
    Question 203
    CBSEENCH12009663
    Question 204
    CBSEENCH12009664
    Question 206
    CBSEENCH12009666

    ___________ and ___________ bases are found un nucleic acids.

    Solution
    Purine, Pyrimidine
    Question 212
    CBSEENCH12009672
    Question 213
    CBSEENCH12009673
    Question 216
    CBSEENCH12009676
    Question 218
    CBSEENCH12009678
    Question 219
    CBSEENCH12009679
    Question 221
    CBSEENCH12009681
    Question 222
    CBSEENCH12009682
    Question 223
    CBSEENCH12009683

    Ribose sugar is a component of

    • DNA

    • RNA

    • Glucose

    • Wax

    Solution

    B.

    RNA

    Question 224
    CBSEENCH12009684
    Question 225
    CBSEENCH12009685
    Question 227
    CBSEENCH12009687

    Name the disaccharide which on hydrolysis give a mixture of glucose and fructose.

    Solution

    Sucrose is the disaccharide which on hydrolysis give mixture of glucose and fructose.
    C12H22O11 + H2O ---> C6H12O6  + C6H12O6 
    sucrose                          glucose        fructose

    Question 228
    CBSEENCH12009688

    Name two purine bases present in DNA.

    Solution

    Two purine bases are:
    i)  Adenine
    ii) Guanine 

    Question 229
    CBSEENCH12009689

    Why is cellulose in our diet not nourshing?

    Solution

    Cellulose in our diet is not nourishing as we do not have an enzyme capable of breaking cellulose molecules into monosaccharides.

    Question 230
    CBSEENCH12009690

    Name one important function of nucleic acids in our bodies.

    Solution

    Nucleic acids are known as polynucleotides as they are long-chain polymers of nucleotides.
    Two main functions of nucleic acids are:
    (i) DNA is responsible for the transmission of inherent characters from one generation to the next. This process of transmission is called heredity.
    (ii) Nucleic acids (both DNA and RNA) are responsible for protein synthesis in a cell.
    Even though the proteins are actually synthesised by the various RNA molecules in a cell, the message for the synthesis of a particular protein is present in DNA.

    Question 231
    CBSEENCH12009691

    Name the purines present in DNA.

    Solution

    Adenine.

    Question 232
    CBSEENCH12009692

    Give structural difference is there between α-glucose and β-glucose?

    Solution

    Structural difference between α-glucose and β-glucose.

    Question 233
    CBSEENCH12009693

    How do amino acids from proteins?

    Solution

    Amino acids are linked together by peptide bonds, thereby forming a long chain. Peptide bonds are formed by a biochemical reaction that extracts a water molecule as it joins the amino group of one amino acid to the carboxyl group of a neighbouring amino acid and hence forming a long chain of the protein.

    Question 234
    CBSEENCH12009694

    Define mutation.

    Solution

    Mutation is the permanent alteration of the nucleotide sequence of the genome of an organism, virus, or extrachromosomal DNA or other genetic elements.

    Question 236
    CBSEENCH12009696

    What is nucleotide?

    Solution

    A nucleotide is a phosphate ester of nucleoside and consists of a purine or pyrimidine base, the 5-carbon sugar and one or more phosphate groups.

    Nucleotide =Base+Sugar+Phosphate

    Question 237
    CBSEENCH12009697

    What type of bonding occurs in β-pleated structure of proteins?

    Solution

    Intermolecular hydrogen bonding occurs in  the β-pleated structure of proteins

    Question 238
    CBSEENCH12009698

    What is meant by primary structure of proteins?

    Solution

    The primary structure of a protein is the linear sequence of amino acids.The amino acids in the primary structure are held together by covalent bonds, which are made during the process of protein synthesis (translation).

    Question 239
    CBSEENCH12009699

    Deficiency of which vitamin causes
    (i) rickets, (ii) Scurvy?

    Solution

    i) Vitamin D
    ii) Vitamin C

    Question 240
    CBSEENCH12009700

    Differentiate between aldose and Ketose ? 

    Solution

    Aldose: This is a type of monosaccharide that contains an aldehyde group on its carbon skeleton. Generally, there is one aldehyde group per each monosaccharide molecule. The aldehyde group is a reactive chemical group denoted as (-CH=O). The chemical formula of aldose is written as Cn(H2O)n.
    Ketose: Ketose is a type of monosaccharide where the carbon skeleton contains a ketone group.he ketone group is a reactive chemical group denoted as (-C=O). The simplest form of ketose is the sugar molecule made up of three Carbon atoms, the middle on with the ketone group. Just as aldoses, ketoses also have many stereogenic centres within the Carbon chain.

    Question 241
    CBSEENCH12009701

    Mention two structural differences between amylose and amylopectin.

    Solution
    Structural differences between amylose and amylopectin.
    In amylose the 1-4 glycosidic .

    In amylopectin there si two linkage such as 1-6 glycosidic or 1-4 glycosidic.
    Question 242
    CBSEENCH12009702

    What are enzymes? Discuss their functions? 

    Solution

    Enzymes act as catalysts for organic biochemical reactions.An example is the digestion of food, absorption of appropriate molecules and ultimately production of energy. This process involves a sequence of reactions and all these reactions occur in the body under very mild conditions. This occurs with the help of certain biocatalysts called enzymes.For example, the enzyme that catalyses hydrolysis of maltose into glucose is named as maltase.


    Question 243
    CBSEENCH12009703

    How does DNA differ from RNA with respect to (a) Sugar and (b) base residues?

    Solution

    Deoxyribonucleic acid (DNA) and ribonucleic acid
    (RNA).In DNA molecules, the sugar moiety is β-D-2-deoxyribose whereas, in RNA molecule, it is β-D-ribose.

    DNA contains four bases viz. adenine (A), guanine (G), cytosine (C) and thymine (T). RNA also contains four bases, the first three bases are same as in DNA but the fourth one is uracil (U).

    Question 244
    CBSEENCH12009704

    What are the different types of RNA found in the cells of organisms? What are their functions?

    Solution

    RNA molecules are of three types and they perform different functions. They are named as messenger
    RNA (m-RNA), ribosomal RNA (r-RNA) and transfer RNA (t-RNA).

    messenger RNA (m-RNA):
    It carries the message, genetic information from DNA to the ribosomes where protein synthesis takes places. It reads the message in the group of three bases. The triplet of bases is called condon. m-RNA is a short -lived molecule.

    Transfer RNA (t-RNA):
    It acts as a carrier of amino acids. The t-RNA reads the codons expressed in m-RNA on the ribosomal particle. Each triplet of t-RNA thus carries the specific amino acid and transfers it to the proper location on the ribosomal particle. All t-RNA molecules have an L-shaped tertiary structure. The hydrophobic interaction is a major stabilising force in the tertiary structure of t-RNA.
    Ribosomal RNA (r-RNA)
    Ribosomal RNA (r-RNA) is an integral part of ribosomes that carries the genetic information from DNA to the ribosomes where actually the protein synthesis takes place.

    Question 245
    CBSEENCH12009705
    Question 246
    CBSEENCH12009706

    What are vitamins? Classify them into water soluble and insoluble vitamins.

    Solution

    Vitamins are organic compounds required in the diet in small amounts to perform specific biological function for normal maintenance of optimum growth and health of the oragnism.
     Vitamins are classified into two groups depending upon their solubility.
    i) Fat soluble vitamins: Vitamins which are soluble in fat and oils but insoluble in water are kept in this group. For example Vitamin A, D, etc.
    ii) Water soluble vitamins: vitamins which are soluble in water known as water soluble vitamins. For example vitamins B and vitmain C.

     

    Question 247
    CBSEENCH12009707

    Explain mutarotation. Give its mechanism in case of D-glucose.

    Solution

    The spontaneous change in specific rotation of an optically active compound is called mutarotation.All reducing sugars undergo mutarotation. Glucose show mutarotation because during the formation of hemiacetal, another asymmetric carbon is produced (C-1) which can exist in two forms,


    Question 248
    CBSEENCH12009708

    Explain the following:
    Denaturation of proteins.  

    Solution

    Protein found in a biological system with a unique three-dimensional structure and biological activity is called a native protein. When a protein in its native form, is subjected to physical change like a change
    in temperature or chemical change like a change in pH, the hydrogen bonds are disturbed. Due to this, globules unfold and helix get uncoiled and protein loses its biological activity. This is called denaturation of the protein. 

    Question 249
    CBSEENCH12010061

    Which one of the following is a disaccharide: Starch, Maltose, Fructose, Glucose ?

    Solution

    Maltose is a disaccharide, as it consists of two   -D-glucose units. Starch is a polysaccharide, while glucose and fructose are monosaccharides

    Question 250
    CBSEENCH12010062

    What is the difference between fibrous protein and globular protein?

    Solution

    Fibrous Proteins

    Globular Proteins

    They are fibre-like structures formed by polypeptide chains. Such proteins are held together by strong hydrogen and disulphide bonds.

    The polypeptide chains in these proteins are folded around themselves, giving these proteins a spherical structure.

    They are usually insoluble in water.

    They are usually soluble in water.

    They are structural proteins. For example, keratin is present in nails and hair, collagen is present in tendons and myosin is present in muscles.

    They are functional proteins. For example, most enzymes and some hormones like insulin.

     

    Question 251
    CBSEENCH12010063

    Write the name of vitamin whose deficiency causes bone deformities in children.

    Solution

    Deficiency of vitamin D causes bone deformities in children.

     

    Question 252
    CBSEENCH12010093

    Which of the two components of starch is water soluble?

    Solution

    Starch contains two components:  Amylose and Amylopectin. Amylose is the water-soluble component. 

    Question 253
    CBSEENCH12010117

    Deficiency of which vitamin causes night-blindness ?

    Solution

    Night blindness is caused due to the deficiency of vitamin A.

    Question 254
    CBSEENCH12010118

    Name the base that is found in nucleotide of RNA only.

    Solution

    Uracil is the base that is found only in the nucleotide of RNA.

    Question 255
    CBSEENCH12010119

    Glucose on reaction with HI gives n-hexane. What does it suggest about the structure of glucose?

    Solution

    The reaction of glucose with HI giving n-hexane suggests that all the six carbon atoms are linked in a straight chain, as shown in the reaction given below:

     CHO-(CHOH)4-CH2OH   rightwards arrow from increment to HI of   CH3-CH2-CH2-CH2-CH2-CH2

     

    Question 256
    CBSEENCH12010144

    What are three types of RNA molecules which perform different functions?

    Solution

    There are three different types of RNA molecules:
    (i) Messenger RNA (mRNA)

    (ii) Transfer RNA (tRNA)

    (iii) Ribosomal RNA (rRNA)

    Question 257
    CBSEENCH12010200

    What is meant by (i) peptide linkage (ii) biocatalysts?

    Solution

    (i) Peptide linkage: a peptide bond is a chemical bond formed between two molecules when the carboxyl group of one molecule reacts with the amino group of the other molecule, releasing a molecule of water (H2O). This is a dehydration synthesis reaction (also known as a condensation reaction) and usually, occurs between amino acid. Peptide linkage is responsible for the primary structure of protein.

    A peptide bond is a chemical bond formed between two molecules when the carboxyl group of one molecule reacts with the amino group of the other molecule, releasing a molecule of water (H2O). This is a dehydration synthesis reaction (also known as a condensation reaction) and usually, occurs between amine. Peptide linkage is responsible for the primary structure of protein

    (ii) Biocatalysis is catalysis in living (biological) systems in which natural catalysts, such as protein enzymes, perform chemical transformations on organic compounds. For example DNA polymerization by DNA polymerase or Joining of DNA by DNA ligases.

    Question 258
    CBSEENCH12010201

    Write any two reactions of glucose which cannot be explained by the open chain structure of glucose molecule.

    Solution

    The following two reactions of glucose cannot be explained by the open chain structure of glucose.

    (i)  Despite having the aldehyde group glucose does not give 2, 4-DNP test, Schiff’s test and it does not form the hydrogen sulphite addition product with NaHSO3.

    (ii) The pentaacetate of glucose does not react with hydroxylamine indicating the absence of free- CHO group.

    Question 259
    CBSEENCH12010238

    What is essentially the difference between α-form of glucose and β-form of glucose? Explain.

    Solution

    The α-form of glucose and β-form of glucose can be distinguished by the position of the hydroxyl group on the first carbon atom.

    In open chain α-glucose, the hydroxyl group on the first carbon atom is towards the right whereas, in the closed ring α-glucose, the hydroxyl group on the first carbon atom is below the plane of the ring.

    On the other hand, in open chain β-glucose, β-glucose, the hydroxyl group on the first carbon atom is towards the left whereas, in the closed ring β-glucose, the hydroxyl group on the first carbon atom is above the plane of the ring.

    The structures of open and cyclic α-form and β-form of glucose can be drawn as follows.

    Question 260
    CBSEENCH12010239

    Describe what you understand by the primary structure and secondary structure of proteins.

    Solution

    Primary structure of proteins: Each polypeptide chain in a protein has amino acids linked with each other in a specific sequence. This sequence of amino acids is said to be the primary structure of proteins.

    2. The secondary structure of proteins: The secondary structure of proteins refers to the shape in which a long polypeptide can exist. The two different secondary structures possible are α-helix structure and β-pleated sheet structure.

    (i) α-Helical structure: In α-Helix structure, a polypeptide chain forms all possible hydrogen bonds by twisting into a helix with -NH group of each amino acid residue and hydrogen bonded to >C=O of an adjacent turn of the helix. The structure can be drawn as follows.

    (ii) β-pleated structure: In a β-pleated structure, all peptide chains are stretched out to nearly maximum extensions and then laid side by side which are held together by intermolecular hydrogen bonds.

    Question 261
    CBSEENCH12010275

    (i) Write the product obtained when D-glucose reacts with H2N - OH.
    (ii) Amino acids show amphoteric behaviour. Why?
    (iii) Why cannot vitamin C be stored in our body?

    Solution

    (i) When D-glucose reacts with NH2OH, an aldoxime is formed.


    (ii) In aqueous solutions, the carboxyl groups of amino acids lose a proton. Amino groups of amino acids, on the other hand, accept a proton, giving rise to a dipolar ion known as zwitter ion.

     

    This is neutral, but contains both positive and negative charges. In the zwitter ionic form, amino acids show amphoteric behaviour as they react with both acids and bases.

    (iii) Vitamin C is water soluble and is readily excreted in urine. Hence, it cannot be stored in our body.

    Question 262
    CBSEENCH12010295

    Write the name of linkage joining two amino acids.

    Solution

    The linkage which joins the two amino acids is known as peptide linkage.

    Question 264
    CBSEENCH12010330

    Write a reaction which shows that all the carbon atoms in glucose are linked in a straight chain.

    Solution

    When glucose is heated with an excess of Hl, it gives n-hexane.

    Question 265
    CBSEENCH12010351

    Define the following as related to proteins:

    (i) Peptide linkage

    (ii) Primary structure

    (iii) Denaturation

    Solution

    (i) Peptide linkage:

    The amide formed between -COOH group of one molecule of an amino acid and –NH2 group of another molecule of the amino acid by the elimination of a water molecule is called a peptide linkage.

     

    (ii) Primary structure:

    The primary structure of a protein refers to the specific sequence in which various amino acids are present in it, i.e., the sequence of linkages between amino acids in a polypeptide chain. The sequence in which amino acids are arranged is different in each protein. A change in the sequence creates a different protein.

    (iii) Denaturation:

    In a biological system, a protein is found to have a unique 3-dimensional structure and a unique biological activity. In such a situation, the protein is called native protein. However, when the native protein is subjected to physical changes such as a change in temperature or chemical changes such as a change in pH, its H-bonds are disturbed. This disturbance unfolds the globules and uncoils the helix. As a result, the protein loses its biological activity. This loss of biological activity by the protein is called denaturation. During denaturation, the secondary and the tertiary structures of the protein get destroyed, but the primary structure remains unaltered.

    One of the examples of denaturation of proteins is the coagulation of egg white when an egg is boiled.

    Question 266
    CBSEENCH12010377

    (i) Write the name of two monosaccharides obtained on hydrolysis of lactose sugar.

    (ii) Why Vitamin C cannot be stored in our body?

    (iii) What is the difference between a nucleoside and nucleotide?

    Solution

    (i) Upon hydrolysis, lactose produces one molecule of D-glucose and one molecule of D-galactose..

    (ii) Vitamin C is water-soluble in nature. It cannot be stored in the human body as it repeatedly gets eliminated through urine.

    (iii)A nucleoside is formed by the attachment of purine or pyrimidine base to the 1- position of a pentose sugar.
    On the other hand, a nucleotide is a unit formed by the attachment of nucleoside to phosphoric acid at the 5′-position of the sugar moiety.

    Question 267
    CBSEENCH12010396

    i) Write the structural difference between starch and cellulose.
    ii) What type of linkage is present in Nucleic acid ?
    iii) Give one example each for fibrous protein and globular protein.

    Solution
    i) Cellulose is mostly linear chains of glucose molecules linked together by beta 1,4 glycosidic bonds whereas starch is found in both linear and branched chains.
    ii) Phosphodiester linkage is present in the nucleic acid.
    iii) Fibrous protein –  myosin
         protein          -   haemoglobin 
    Question 268
    CBSEENCH12010428

    Write the main structural difference between DNA and RNA. Of the four bases, name those which are common to both DNA and RNA.

    Solution

    The structural differences between DNA and RNA are as follows:

    DNA

    RNA

    1.

    The sugar moiety in DNA molecules is b-D-2 deoxyribose.

    1.

    The sugar moiety in RNA molecules is b-D-ribose.

    2.

    DNA contains uracil (U). It does not contain thymine (T).

    2.

    RNA contains thymine (T). It does not contain uracil (U).

    3.

    The helical structure of DNA is double-stranded.

    3.

    The helical structure of RNA is single-stranded.

    Question 269
    CBSEENCH12010429

    Write such reactions and facts about glucose which cannot be explained by its open chain structure.

    Solution

    (i) Aldehydes give 2, 4-DNP test, Schiff’s test, and react with NaHSO4 to form the hydrogen sulphite addition product. However, glucose does not undergo these reactions.

    (ii) The pentaacetate of glucose does not react with hydroxylamine. This indicates that a free -CHO group is absent from glucose.

    (iii) Glucose exists in two crystalline forms a and b. The a-form (m.p. = 419 K) crystallises from a concentrated solution of glucose at 303 K and the b-form (m.p = 423 K) crystallises from a hot and saturated aqueous solution at 371 K. This behaviour cannot be explained by the open chain structure of glucose.
    Question 270
    CBSEENCH12010448

    What are the products of hydrolysis of sucrose?

    Solution

    Hydrolysis of sucrose gives glucose and fructose as products.

    Question 271
    CBSEENCH12010467

    Define the following terms as related to proteins:

    (i) Peptide linkage
    (ii) Primary structure
    (iii) Denaturation

    Solution

    (i) Peptide linkage: It is the amide formed between the −COOH and −NH2 groups of two amino acid molecules.

     

    (ii) Primary structure of proteins: Proteins contain one or more polypeptide chains and each chain has amino acids linked with each other in a specific sequence. This sequence of amino acids represents the primary structure of proteins.

    (iii) Denaturation: It is the loss of biological activity of proteins because of some physical changes like changes in pH and temperature, due to which the unfolding of globules and the uncoiling of helix take place.
    Examples: Coagulation of egg white on boiling and curdling of milk.

    Question 273
    CBSEENCH12010576

    Define the following with an example:

    Polysaccharides

    Solution

    Polysaccharides are polymeric carbohydrate molecules composed of long chains of monosaccharide units bound together by glycosidic linkages for example starch.

    Question 274
    CBSEENCH12010577

    Define the following with an example:

    Denatured protein

    Solution

    When a protein in its native form, is subjected to physical change like a change in temperature or chemical change like a change in pH, the hydrogen bonds are disturbed. Due to this, globules unfold and helix gets uncoiled and protein loses its biological activity. This is called denaturation of the protein.

    Question 275
    CBSEENCH12010578

    Define the following with an example:

    Essential amino acids

    Solution

    The amino acid which cannot be synthesised in the body and must be obtained from the diet are known as essential amino acid. 

    The 9 essential amino acids are histidine, isoleucine, leucine, lysine, methionine, phenylalanine, threonine, tryptophan, and valine.

    Question 276
    CBSEENCH12010579

    Write the product when D-glucose reacts with conc. HNO3

    Solution

    When D-glucose react with (conc.) Nitric acid, it forms Saccharic acid.

    Question 277
    CBSEENCH12010580

    Amino acids show amphoteric behaviour. Why?

    Solution

    In aqueous solution, the carboxyl group of an amino acid can lose a proton and the amino group can accept a proton to give a dipolar ion known as zwitter ion.

    Therefore, in zwitter ionic form, the amino acid can act both as an acid and as a base. Thus, amino acids show amphoteric behaviour.

    Question 278
    CBSEENCH12010581

    Write one difference between α -helix and β -pleated structures of proteins.

    Solution

    α - helix: It has a polypeptide chain which forms all possible hydrogen bonds twisting it into a right-handed screw. (helix)

    β - pleated: It has peptide chain which is stretched out to nearly maximum extension and then laid side by side which are held by intermolecular hydrogen bonds.

    Question 279
    CBSEENCH12010619

    The absolute configuration of

    is:

    • (2S, 3R)

    • (2S, 3S)

    • (2R, 3R)

    • (2R, 3S)

    Solution

    A.

    (2S, 3R)


    For C-2 order of priority of substituents is 
    OH> CH(Cl)(CH3)>COOH

    For C-3, order of priority of substituents is 
    Cl> CH(OH)COOH > CH3
    Question 281
    CBSEENCH12010668

    Which one of the following bases is not present in DNA?

    • Quinoline

    • Adenine

    • Cytosine

    • Thymine

    Solution

    A.

    Quinoline

    Quinoline is an alkaloid, it is not present in DNA. DNA  has four nitrogen bases in adenine, guanine, cytosine and  thymine

    Question 282
    CBSEENCH12010684

    Synthesis of each molecule of glucose in photosynthesis involves

    • 18 molecules of ATP

    • 10 molecules of ATP

    • 8 molecules of ATP

    • 6 molecules of ATP

    Solution

    A.

    18 molecules of ATP

    6CO2 + 12NADP.2H + 18 ATP → C6H12O6 + 18 P +12NADP +18 ADP

    Question 283
    CBSEENCH12010695

    Which of the following compounds can be detected by Molisch’s test?

    • Nitro compounds

    • Sugars

    • Amines

    • Primary alcohols

    Solution

    B.

    Sugars

    Molisch’s Test: when a drop or two of the alcoholic solution of α–naphthol is added to sugar solution and then conc. H2SO4 is added along the sides of the test tube, the formation of violet ring takes place at the junction of two liquids.

    Question 284
    CBSEENCH12010709

    The presence or absence of hydroxy group on which carbon atom of sugar differentiates RNA and DNA.

    • 1st

    • 2nd

    • 3rd

    • 4th

    Solution

    B.

    2nd

    RNA and DNA has ribose and deoxyribose sugars, which differs in absence of hydroxy group at 2 nd carbon.

    Question 285
    CBSEENCH12010747

    Biuret test is not given by 

    • proteins

    • carbohydrates

    • polypeptides

    • urea

    Solution

    B.

    carbohydrates

    Biuret test is given by the compounds having peptide bond which is not present in carbohydrate.  Biuret Test produces violet colour on addition of dilute  CuSO4 to an alkaline solution of a compound containing peptide linkage.

    Question 286
    CBSEENCH12010759

    Which of the following compounds will behave as a reducing sugar in an aqueous KOH solution?

    Solution

    A.

    Ester in presence of Aqueous KOH solution give SNAE reaction so following reaction takes place

    Question 287
    CBSEENCH12010788

    The two functional groups present in a typical carbohydrate are

    • -OH and -COOH

    • -CHO and -COOH

    • >C = O and - OH

    • -OH and -CHO 

    Solution

    C.

    >C = O and - OH

    Carbohydrates are primarily hydroxyl carbonyl compound hence > C = O and –OH are present.

    Question 288
    CBSEENCH12010804

    α-D-(+)-glucose and β-D-(+)-glucose are

    • conformers

    • epimers

    • anomers

    • enantiomers 

    Solution

    C.

    anomers

    α - D (+) glucose and β - D (+) glucose are anomers. 

    Question 289
    CBSEENCH12010818

    The secondary structure of a protein refers to 

    • α-helical backbone 

    •  hydrophobic interactions

    • sequence of α-amino acids

    • fixed configuration of the polypeptide backbone

    Solution

    A.

    α-helical backbone 

    The secondary structure of proteins involves α − helical back bond and β − sheet structures. These structures are formed as a result of H-bonding between different peptide groups.

    Question 293
    CBSEENCH12010973
    Question 295
    CBSEENCH12010984

    Glucose on prolonged heating with HI gives

    • 6-iodohexanal

    • n-Hexane

    • 1-Hexene

    • Hexanoic acid

    Solution

    B.

    n-Hexane

    The reaction of glucose with HI giving n-hexane suggests that all the six carbon atoms are linked in a straight chain, as shown in the reaction given below:

    Question 296
    CBSEENCH12011035

    In a protein molecule various amino acids are linked together by

    • β-glycosidic bond
    • peptide bond

    • dative bond

    • α - glycosidic bond

    Solution

    B.

    peptide bond

    Two amino acids on the protein are linked by a peptide bond. For example. Glycyllalanine is formed when carboxyl group of glycine combines with the amino group of alanine.

    Question 297
    CBSEENCH12011049

    Which of the following statement is false?

    • Ca2+ ions are important in blood clotting

    • Ca2+ ions are not important in maintaining the regular beating of the heart.

    • Mg2+ ions are important in the green parts of plants

    • Mg2+ ions form a complex ATP

    Solution

    B.

    Ca2+ ions are not important in maintaining the regular beating of the heart.

    Ca2+ ions are very important for maintaining the regular heart beating.

    Question 298
    CBSEENCH12011055

    The correct statement regarding RNA and DNA, respectively is

    • The sugar component in RNA is ribose and sugar component in DNA is 2' deoxyribose

    • The sugar component in RNA is arabinose and the sugar component in DNA is ribose

    • The sugar component in RNA is 2'-deoxyribose and the sugar component in DNA is arabinose

    • The sugar component in RNA is arabinose and the sugar component in DNA is 2' deoxyribose.

    Solution

    A.

    The sugar component in RNA is ribose and sugar component in DNA is 2' deoxyribose

    In DNA, two helically twisted strands connected together by steps. Each strand consists of alternating molecules of deoxyribose at 2'-position and phosphate groups. 
    On another hand, in RNA, the pentose sugar has an identical structure with deoxyribose sugar except that there is an -OH group instead of -H on carbon atom2'. Hence it is only called ribose.

    Question 299
    CBSEENCH12011056

    Which one given below is a non - reducing sugar?

    • Lactose

    • Glucose

    • Sucrose

    • Maltose

    Solution

    C.

    Sucrose

    sucrose is non-reducing sugar because it has one -CHO group.

    Question 300
    CBSEENCH12011059

    The function of 'sodium pump' is a biological process operating in each and every cell of all animal. Which of the following biologically important ions is also a constituent of this pump?

    • Ca2+

    • Mg2+

    • K+

    • Fe2+

    Solution

    C.

    K+

    The sodium pump is also known as a sodium Potassium pump. This pump is important contributor to action potential produced by nerve cells. The process of moving sodium potassium ions across the cell membranes is active transport process involving the hydrolysis of ATP to provide the necessary energy. 

    Question 302
    CBSEENCH12011149

    Which one of the following statement is incorrect about enzyme catalysis?

    • Enzymes are mostly proteinous in nature

    • Enzyme action is specific

    • Enzymes are denaturated by ultraviolet rays and at high temperature

    • Enzymes are least reactive at optimum temperature

    Solution

    D.

    Enzymes are least reactive at optimum temperature

    Most of the enzymes have proteinous nature. They are highly specific and get denaturated by high temperature or UV rays. At optimum temperature, which is generally in between 25-35o, enzyme activity is maximum.

    Question 303
    CBSEENCH12011151

    Deficiency of vitamin Bcauses the disease

    • convulsions

    • beri-beri

    • cheilosis

    • sterility

    Solution

    B.

    beri-beri

    Deficiency of vitamin B1 cause beri-beri in which they occur a loss of appetite and vigour, weak heart beat etc. 

    Question 304
    CBSEENCH12011165

    Which one of the following sets of monosaccharides forms sucrose?

    • α-D-galactopyranose and α-D- glucopyranose
    • α-D-glucopyranose and β-D-fructofuranose
    • β-D-glucopyranose and α-D-fructofuranose
    • α-D-glucopyranose and β-D-fructopyranose

    Solution

    B.

    α-D-glucopyranose and β-D-fructofuranose

    Sucrose is composed of α-D-glucopyranose and β-D-fructofuranose units which are joined by α, β-glycosidic linkage between C-1 of the glucose unit and C-2 of the fructose unit.

    Question 306
    CBSEENCH12011228

    Which of the following is not a fat soluble vitamin?

    • Vitamin- B - complex

    • Vitamin -D

    • Vitamin -E

    • Vitamin -A

    Solution

    A.

    Vitamin- B - complex

    Vitamin - A, D and E are fat soluble vitamins whereas vitamin - B complex is a water soluble vitamin

    Question 308
    CBSEENCH12011263

    Which one of the following species does not exist under normal conditions?

    • (+)Sucrose

    • (+)Lactose

    • (+) Maltose

    • (-) Fructose

    Solution

    A.

    (+)Sucrose

    Reducing sugars that exist in hemiacetal and hemiketal forms, undergo mutarotation in aqueous solution.
    Among the given carbohydrates, only sucrose is a non-reducing sugar as in it the hemiacetal and hemiketal groups of glucose and fructose are linked together through O-atom and thus, not free. Due to the absence of free hemiacetal or hemiketal group, sucrose does not exhibit mutarotation.

    Question 309
    CBSEENCH12011295

    Fructose reduces Tollen's reagent due to 

    • asymmetric carbons

    • primary alcoholic group

    • secondary alcoholic group

    • enolization of fructose followed by conversion to the aldehyde by base

    Solution

    D.

    enolization of fructose followed by conversion to the aldehyde by base

    In aqueous solution, fructose is enolized and then converted into aldehyde in basic medium. All aldehydes generally reduces Tollen's reagent thus fructose also reduces Tollen's reagent.

    Question 310
    CBSEENCH12011311

    The segment of DNA, which acts as the instrumental manual for the synthesis of the protein is 

    • nucleotide

    • ribose

    • gene

    • nucleoside

    Solution

    C.

    gene

    The segment of DNA Which acts as the instrumental manual for the synthesis of the protein is a gene. Every protein in a cell has a corresponding gene.

    Question 311
    CBSEENCH12011341

    In DNA. the complimentary bases are 

    • Adenine and thymine; guanine and cytosine

    • Adenine and thymine; guanine and uracil

    • Adenine and guanine, thymine: Guanine and uracil

    • Uracil and adenine; cytosine and guanine

    Solution

    A.

    Adenine and thymine; guanine and cytosine

    Deoxyribonucleic acid (DNA) has the purine bases adenine and guanine and pyrimidine bases thymine and uracil. According to base pairing rule adenine paired with thymine (A=T) and cytosine paired with guanine  straight C identical to straight G 

    Question 312
    CBSEENCH12011354

    Which one of the following vitamins is water soluble? 

    • vitamin - B

    • vitamin - E

    • vitamin - K

    • vitamin - A

    Solution

    A.

    vitamin - B

    Vitamins are classified  as
    (i) Fat soluble vitamin: A, D, E, K
    (ii) Water soluble; Vitamin B complex and c S vitamin B is water soluble.

    Question 313
    CBSEENCH12011364

    RNA and DNA are chiral molecules, their chirality is due to:

    • L -sugar component

    • chiral bases

    • chiral phosphate ester units

    • D -sugar component

    Solution

    D.

    D -sugar component

    RNA and DNA molecules have ribose and deoxyribose sugar respectively. Both are chiral, their chirality is due to D -ribose or deoxyribose sugar components. 

    Question 314
    CBSEENCH12011389

    During the process of digestion, the proteins present in food materials are hydrolysed in amino acids. The two enzymes involved in the process

    Proteins space rightwards arrow with Enzyme space left parenthesis straight A right parenthesis on top space Polypeptides
space space space space space space space space space space space space space space rightwards arrow with Enzyme space left parenthesis straight B right parenthesis on top space Amino space acids comma
    are respectively:

    • amylase and maltase

    • diastase and lipase

    • pepsin and trypsin

    • invertase and zymase

    Solution

    C.

    pepsin and trypsin

    In the process of digestion, the proteins present in food material are hydrolysed to an amino acid. In this process two enzymes pepsin and trypsin are involved as follows:
    Proteins space rightwards arrow from left parenthesis Enzyme apostrophe straight A apostrophe to Pepsin of space Polypeptide rightwards arrow from left parenthesis Enzyme space apostrophe straight B apostrophe to Trypsin of space Amino space acid

    Question 315
    CBSEENCH12011390

    The human body does not produce:

    • DNA

    • Vitamins

    • Hormones

    • enzymes

    Solution

    B.

    Vitamins

    The organic compounds other than carbohydrates proteins, which maintain normal growth and nutrition in the human body (but not produced in the human body) are called vitamins.

    Question 316
    CBSEENCH12011399

    Which one of the following is a peptide hormone?

    • Glucagon

    • Testosterone

    • Thyroxin

    • Adrenaline

    Solution

    A.

    Glucagon

    Glucagon is a peptide hormone because it is peptide linkage is present.

    Question 317
    CBSEENCH12011421

    Which of the following statements is not correct?

    • Insulin maintains sugar level in the blood of ahuman body

    • Ovalbumin is a simple food reserve in egg-white

    • Blood proteins thrombin and fibrinogen are involved in blood clotting

    • Denaturation makes the proteins more active

    Solution

    D.

    Denaturation makes the proteins more active

    Due to denaturation of proteins, globules unfold and helix get uncoiled and protein loses its biological activity.

    Question 318
    CBSEENCH12011451

    The difference between amylose and amylopectin is

    • Amylopectin have 1 → 4 α-linkage and 1 → 6 α-linkage

    • Amylose have 1 → 4 α-linkage and 1 → 6 β-linkage

    • Amylose is made up of glucose and galactose

    • Amylopectin have 1 → 4 α-linkage and 1 → 6 β-linkage

    Solution

    A.

    Amylopectin have 1 → 4 α-linkage and 1 → 6 α-linkage

    In amylose the 1-4 glycosidic.

    In amylopectin there is two linkage such as 1-6 glycosidic or 1-4 glycosidic.

    Amylose and Amylopectin are polymers of α-D-glucose, so β link is not possible. Amylose is linear with 1 → 4 α-linkage whereas Amylopectin is branched and has both 1 → 4 and 1 → 6 α-linkages.

    Question 319
    CBSEENCH12011501

    On hydrolysis of starch, we finally get

    • Glucose

    • Fructose

    • Both (a) and (b)

    • Sucrose

    Solution

    A.

    Glucose

    Starch is a polymer of D-glucose units, thus on hydrolysis it only gives glucose.

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