Sponsor Area
Thermodynamics Here is the CBSE Physics Chapter 12 for Class 11 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 11 Physics Thermodynamics Chapter 12 NCERT Solutions for Class 11 Physics Thermodynamics Chapter 12 The following is a summary in Hindi and English for the academic year 2025-26. You can save these solutions to your computer or use the Class 11 Physics.
Derive an expression for the work done during Isothermal expansion
Work done during isothermal expansion of 1 mole of ideal gas
W = ∫ dW
v2
W = ∫ Pd V - - - - ( I )
v1
For 1 mole of gas
PV = RT
P = RT / V
Putting value of P in eqn ( I ).,
v2
W = ∫ RT / V dV
v1
v2
W = RT ∫ 1 / V dV
v1
v2
W= RT [ log e V]
v1
W = RT [ log e V2 - log e V1 ]
W = 2.303 RT log 10 V2 / V1
For constant temperature,
W = 2.303 RT log 10 P2 / P1
Sponsor Area
Sponsor Area
Mock Test Series
