Sponsor Area
Electricity Here is the CBSE सामाजिक विज्ञान Chapter 12 for Class 10 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 10 सामाजिक विज्ञान Electricity Chapter 12 NCERT Solutions for Class 10 सामाजिक विज्ञान Electricity Chapter 12 The following is a summary in Hindi and English for the academic year 2025-26. You can save these solutions to your computer or use the Class 10 सामाजिक विज्ञान.
Show how would you join three resistors, each of resistance 9Ω so that the equivalent resistance of the combination is (i) 13Ω (ii) 6Ω?
The possible way of the combination are:
The resistor of 9Ω can combine parallel and one in series.
(ii) 2 resistors connected in series and one in parallel.
R1 + R2 =
= 9Ω + 9Ω = 18Ω
Now
18Ω and 9Ω are connected
The values of current (I) flowing through a given resistor of resistance (R), for the corresponding values of potential difference (V) across the resistor are as given below:
| V (volts) | 0.5 | 1.0 | 1.5 | 2.0 | 2.5 | 3.0 | 4.0 | 5.0 |
| 1 (amperes) | 0.1 | 0.2 | 0.3 | 0.4 | 0.5 | 0.6 | 0.8 | 1.0 |
Plot a graph between current (I) and Potential difference (V) and determine the resistance (R) of the resistor.
Sponsor Area
Sponsor Area
Mock Test Series
