Electricity

Question

Show how would you join three resistors, each of resistance 9Ω so that the equivalent resistance of the combination is (i) 13Ω (ii) 6Ω?

Solution

The possible way of the combination are:

The resistor of 9Ω can combine parallel and one in series.

WiredFaculty

$(\frac{1}{R_{1}} + \frac{1}{R_{2}}) + R_{3} (\frac{1}{9} + \frac{1}{9}) + 9 (\frac{2}{9}) + 9 4.5 Ω + 9 Ω = 13.5 Ω$

(ii) 2 resistors connected in series and one in parallel.

WiredFaculty

R₁ + R₂ =
= 9Ω + 9Ω = 18Ω

Now

18Ω and 9Ω are connected

$\frac{18 x 9}{18 + 9} = 6 Ω$

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