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Electrostatic Potential and Capacitance
Question
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In the given figure, a diode D is connected to an external resistance R = 100 Ω and an e. m. f of 3.5 V. If the barrier potential developed across the diode is 0.5 V, the current in the circuit will be 


  • 30 mA

  • 40 mA

  • 20 mA

  • 35 mA

Answer

A.

30 mA

Given, external resistance R = 100 Ω and an emf is 3.5 V.
Potential barrier across the diode is 0.5 V


Potential difference on R = 3.5 V - 0.5 V  = 3.0 V
Current in circuit, I = V/R  = 3/100
 = 0.03 A  = 30 mA

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