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Wave Optics
Question
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Find out the wavelength of the electron orbiting in the ground state of the hydrogen atom.

Answer

Radius of ground state of hydrogen atom =0.53A°  = 0.53 x10-10m
According to de Broglie relation 2πr = nλ
For ground state n=1
2 x 3.14 x 0.53 x 10-10= 1 x λ
therefore, λ = 3.32 x10-10 m
= 3.32 A° 

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