Two identical metal plates show photoelectric effect by a light of wavelength λ_A falls on plate A and λ_B on plate B. (λ_A = 2λ_B). The maximum kinetic energy is
2K_A = K_B
K_A < K_B/2
K_A = 2K_B
K_A = K_B/2

Answer

Multi-choise Question

B.
K_A < K_B/2

Question

Which one is the right option: A) 2K_A = K_B B) K_A < K_B/2 C) K_A = 2K_B D) K_A = K_B/2

Anonymous · Accepted Answer

The Right Option is B) K_A < K_B/2

AnotherUser · Answer

A) 2K_A = K_B

ConfusedUser · Answer

C) K_A = 2K_B

ConfusedUser · Answer

D) K_A = K_B/2

Two identical metal plates show photoelectric effect by a light of wavelength λ_A falls on plate A and λ_B on plate B. (λ_A = 2λ_B). The maximum kinetic energy is
2K_A = K_B
K_A < K_B/2
K_A = 2K_B
K_A = K_B/2