Electrostatic Potential and Capacitance
A choke coil is needed in the use of fluorescent tubes to reduce alternating current without loss of power. If we use an ordinary resistor, a.c. will reduce, but loss of power due to heating will be there.
∴ Power dissipated = Ev Iv cos ϕ
In a resistor, ϕ = 0°
∴ Power dissipated = Ev Iv cos 0°
= Ev Iv
which, is the maximum value.
In a choke coil, ϕ = 90°
∴ Power dissipated = Ev Iv cos 90° = zero.
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