Trying to find the right answer to this..

Given, two electrical bulbs. Potential across first bulb, V 1 = 220 V Power of first bulb, P 1 = 40 W Potential across second bulb, V 2 = 220 V Power of second bulb, P 2 = 60 W Now, P = V 2 /R or R = V 2 /P i.e., R &prop; 1/P. Resistance is inversely proportional to power. Therefore, the first bulb having lesser power has higher resistance.

Current Electricity

Question

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Two electric bulbs A and B are marked 220 V, 40 W and 220 V, 60 W respectively. Which one of these bulbs has higher resistance?

Answer

Given, two electrical bulbs.
Potential across first bulb, V₁= 220 V
Power of first bulb, P₁= 40 W
Potential across second bulb, V₂ = 220 V
Power of second bulb, P₂ = 60 W

Now,
P = V²/R or R = V²/P
i.e., R ∝ 1/P.
Resistance is inversely proportional to power.
Therefore, the first bulb having lesser power has higher resistance.