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System of Particles and Rotational Motion
Question
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Five particles of mass 2 kg are attached to the rim of a circular disc of radius 0.1 m and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is

  • 1 kg m2

  • 0.1 kg m2

  • 2 kg m2

  • 0.2 kg m2

Answer

B.

0.1 kg m2

The moment of inertia of given system that contains 5 particles each of mass = 2 kg on the rim of circular disc of radius 0.1 m and of negligible mass is given by :

MI of disc + MI of particle

Since the mass of the disc is negligible

∴ MI of the system = MI of particle

= 5 × 2 × (0.1)2

= 0.1 Kg m2

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