The work done in pulling up a block of wood weighing 2 kN for a length of 10 m on a smooth plane inclined at an angle of 15° with the horizontal is

9.82 kJ

89 kJ

4.35 kJ

5.17 kJ

Answer

5.17 kJ

Here :- Weight of block;ω = 2kN; Distance d =10m

Angle of inclination on the plane α =15⁰

The block will be pulled up on a smooth plane

Hence,force of resistance due to the inclination

F =ωsinα = 2×10³×Sin 15⁰

=2×10³×0.2588

=0.5176 kN

Now work done W = force×displacement =0.1576×10³×10=5.17kJ

Sponsor Area

Some More Questions From Physical World Chapter

Sponsor Area

Sponsor Area