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Mechanical Properties of Fluids
Question
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The black oxide of copper is prepared in four different ways and the following observations noted:

Copper (in g)

Copper oxide (in g)

5.015

6.284

8.286

10.357

18.443

23.169

12.011

15.051

 

What do you infer from this data?

Answer

Fraction of the copper present in the oxide of copper is:

(a) 5.015/6.284 = 0.798

(b) 8.286/10.357 = 0.800

(c) 18.443/23.169 = 0.796 

(d) 12011/15.051 = 0.798

Since the fraction of the copper present in the oxide of copper is constant, this proves the law of constant proportions. 

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