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Motion in A Plane
Question
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A car travelling at 60 km/h overtakes another car travelling at 42 km/hr. Assuming each car to be 5.0 m long, find the time taken during the overtaking and the total road distance used for the overtake? 

Answer

Total distance to be travelled  for overtaking the car = 5.0  +5.0 = 10. 0 m 
Relative velocity of first car w.r.t second car = 60 - 42 = 8 km/hr
     = 8 x 1000/ (60 x 60)
      = 50 m/s
Time taken, t = 10/5 = 2 s.
Road distance used for overtaking = distance travelled by first car in 2 s + length of first car
= [ 60 x 1000 / (60 x60)] x 2+ 5
= 38.33 m

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