Motion in A Plane
Two buses started simultaneously towards each other from towns A and B which are 480 km apart. It took the first bus travelling from A to B eight hours to cover the distance and the second bus travelling from B to A, ten hours. Determine when the buses will meet after starting and at what distance from A.
Here, distance between two towns A and B, S = 480 km
v1 = S/8 and
v2 = S/10
If these buses meet after time t, then
S/8 x t + S/10 x t = S
On solving, we get
t = 40/9 hours
Therefore, distance from A = 480/80 x 40/9 = 800/3 = 266.7 km
Sponsor Area
Sponsor Area
Sponsor Area