A particle has the following displacements in succession i) 12 m towards east ii) 5 m towards north and iii) 6 m vertically. Find the magnitude of the resultant displacement?
Answer
Short Answer
Here, we have x = 12 m ; y = 5 m ; z = 6m Then, resultant vector is given by, r = (x2 + y2 + z2 ) 1/2 = ( 122 + 52 + 62)1/2 = (205)1/2 = 14.31 m
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