Trying to find the right answer to this..

Mass of the man = M Rate of acceleration of the lift = a m/s 2 Acceleration due to gravity = g m/s 2 which is acting downwards. Weight of the man when the lift is moving downwards = M(g-a) kg

Laws of Motion

Question

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A man of mass M is standing in a lift accelerating down with acceleration a. What is the apparent weight of the man in the lift?

Answer

Mass of the man = M
Rate of acceleration of the lift = a m/s²
Acceleration due to gravity = g m/s² which is acting downwards.
Weight of the man when the lift is moving downwards = M(g-a) kg