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Work, Energy and Power
Question
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A body of mass 1 kg initially at rest is moved by a horizontal force of 0.5 N on a smooth frictionless table. Calculate the work done by the force in 10 seconds. 

Answer

Given, 
Mass, m = 1.0 kg 
Initial velocity, u = 0 m/s
Force = 0.5 N 
Time, t = 10 sec
Now,
Acceleration, a = F/m = 0.5 / 1.0 = 0.5 m/s2 
Now, using the second equation of motion, we have 
                s = ut + 1/2 at2 
i.e.,           s = 0 + 1/2 X (0.5) X (10)2 
                   = 25 m
Therefore, 
Work done, W = F X s
                      = 0.5 X 25
                      = 12.5 Joule
 

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