Measures of Central Tendency
The mean marks obtained in an examination by a group of 100 students were found to be 49.6. The mean marks obtained in the same examination by another group of 200 students were 53.32. Find out the mean of marks obtained by both the groups of students taken together.
Total marks of 300 students
= (49.4 x 100) + (52.32 x 200)
= 4946+10464
=15410
Sponsor Area
The following table gives production yield in kg. per hectare of wheat of 150 arms in a village. Calculate the mean, median and mode production yield.
Production yield (kg. per hectare) |
50-53 |
53-56 |
56-59 |
59-62 |
62-65 |
65-68 |
68-71 |
71-74 |
74-77 |
Number of farms |
3 |
8 |
14 |
30 |
36 |
28 |
16 |
10 |
5 |
The size of land holdings of 380 families in a village is given below. Find the median size of land holdings.
Size of Land Holdings (in acres) |
Number of families |
less than 100 100-200 200-300 300-400 400 and above |
40 89 148 64 39 |
What do you mean by 'Average'?
Pocket expenditures of 6 students are (Rs.) 6,12,18,24,30 and 36 respectively. Find out arithmetic mean.
Name various kinds of statistical averages?
Give formula of weighted averages.
Give formula of calculating arithmetic average of a continuous series.
What is arithmetic mean?
Define median.
Define mode.
Sponsor Area
Sponsor Area