Prove that the function f (x) = 4x³ – 6x² + 3x + 12 is increasing on R

Question

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Anonymous · Accepted Answer

Here f (x) = 4x³ – 6x² + 3x + 12 12 ∴ D_f = R
f ' (x) = 12x²– 12x + 3 = 3(2x – 1)² 4x + 1) = 3(2 x – 1)² ≥ 0 ∀ x ∊ R
∴ f (x) is increasing on R.

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