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Question

In the following, verify that the given functions, (explicit or implicit) is a solution of the corresponding differential equation:
y = cos x + C : y' + sinx = 0

Answer

y = cos x + C
∴ y' = – sin x
⇒ y' + sin x = 0
∴ y = cos x + C is a solution of y' + sin x = 0

Sponsor Area

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Sponsor Area

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Sponsor Area

Entrance Exams Preparation

In the following, verify that the given functions, (explicit or implicit) is a solution of the corresponding differential equation:
y = cos x + C : y' + sinx = 0

Some More Questions From Vector Algebra Chapter

Mock Test Series

NCERT Book Store

NCERT Sample Papers

Entrance Exams Preparation

In the following, verify that the given functions, (explicit or implicit) is a solution of the corresponding differential equation:y = cos x + C : y' + sinx = 0

Some More Questions From Vector Algebra Chapter

Mock Test Series

NCERT Book Store

NCERT Sample Papers

Entrance Exams Preparation

In the following, verify that the given functions, (explicit or implicit) is a solution of the corresponding differential equation:
y = cos x + C : y' + sinx = 0