Quadratic Equations
Let the number of toys produced on that day = x
And, cost of production = (55 – x)
According to the given question,
x (55 – x) = 750
⇒ 55x – x2 – 750 = 0
x2 – 55x + 750 = 0
⇒ x2 – 30x – 25x + 750 = 0
⇒ x(x – 30) – 25(x – 30) = 0
⇒ (x – 30) (x – 25) = 0
⇒ x – 30 = 0 or x – 25 = 0
⇒ x = 30 or x = 25.
Hence, the number of toys produced on that day are 30 or 25.
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