If sin 3θ = cos (θ - 6°) and θ-6° are acute angles, find the value of θ.

Question

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Anonymous · Accepted Answer

we have, sin 3θ = cos (θ - 6°)
⇒ cos (90°-3θ) = cos (θ-6°)
⇒90°-3θ = θ-6°
⇒84° = 4θ
⇒ θ = 21°

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