Constructions
Given: ABCD, DCFE and ABFE are parallelograms.
To Prove: ar(ΔADE) = ar(ΔBCF).
Proof: ∵ ABCD is a || gm
∴ AB || DC ...(1)
| Opposite sides of a || gm are ||
∵ DCFE is a || gm
∴ DC || EF ...(2)
| Opposite sides of a || gm are ||
From (1) and (2),
AB || EF ...(3)
∵ ABCD is a || gm
∴ AD = BC ...(4)
| Opposite sides of a || gm are equal
∵ ΔADE and ΔBCF are on equal bases (∵ AD = BC) and between the same parallels AB and EF.
□∴ ar(ΔADE) = ar(ΔBCF).
∵ Two triangles on the same base (or equal bases) and between the same parallels are equal in areas
Sponsor Area
In the given figure, ABED is a parallelogram in which DE = EC. Show that area (ABF) = area (BEC)
In the following figure, ABCD is a parallelogram and EFCD is a rectangle. Also, AL ⊥ DC. Prove that
(i) ar(ABCD) = ar(EFCD)
(ii) ar(ABCD) = DC x AL.
Sponsor Area
Sponsor Area