If p(x) =x³ - ax² + bx + 3 leaves a rer.idinder -19 when divided by (x + 2) and a remainder 17 when divided by (x - 2), prove that a + b = 6.

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Short Answer

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Ans. a = 1, b = 5

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Anonymous · Accepted Answer

Solution not provided.

Ans. a = 1, b = 5

If p(x) =x³ - ax² + bx + 3 leaves a rer.idinder -19 when divided by (x + 2) and a remainder 17 when divided by (x - 2), prove that a + b = 6.