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Coordinate Geometry
Question
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Find p(0), p(1) and p(2) for each of the following polynomials:
p(t) = 2 + t + 2t2 - t3

Answer

p(t) = 2 + t + 2t2 - t3
∴ p(0) = 2 + 0 + 2(0)2 - (0)3 = 2,
p(1) = 2 + 1 + 2(1)2 - (1)3
= 2 + 1 + 2 - 1 = 4,
and, p(2) = 2 + 2 + 2(2)2 - (2)3
= 2 + 2 + 8 - 8 = 4.

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Some More Questions From Coordinate Geometry Chapter

Which of the following expressions are polynomials in one variable and which are not? State reasons for your answer.

4x2 - 3x + 7

Which of the following expressions are polynomials in one variable and which are not? State reasons for your answer.

x10+ y3 + t50

Write the coefficients of x2 in each of the following:

2 + x2 + x

Write the coefficients of x2 in each of the following:
2 - x2 + x3