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Solutions
Give reasons for the following:
Elevation of the boiling point of 1 M KCl solution is nearly double than that of 1 M sugar solution.
The elevation of boiling point is Δtb = iKbm in both 1M KCl & 1 M sugar. As colligative property depends only on a number of particle and KCl as electrolyte will produce a double number of a particle of sugar. Hence the value van’t hoff factor is twice in 1m KCl then 1M sugar due to which elevation in boiling point is more.
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Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.
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