Coordination Compounds
(a) Write the hybridization and shape of the following complexes:
(i) [CoF6]3–
(ii) [Ni (CN)4]2–
(Atomic number: Co = 27, Ni = 28)
(b) Out of NH3 and CO, which ligand forms a more stable complex with a transition metal and why?
(a)
(i) The atomic number of Co is 27 and its valence shell electronic configuration is 3d74s2.
Co is in +3 oxidation state in the complex [CoF6]3-.
Hence, [CoF6]3- is sp3d2 hybridized and it is octahedral in shape.
(ii) The atomic number of Ni is 28 and its valence shell electronic configuration is 3d84s2.
Ni is in +2 oxidation state in the complex [Ni(CN)4]2–.
Hence, [Ni(CN)4]2– is dsp2 hybridized and it is square planar in shape.
(b) Out of NH3 and CO, CO ligand forms a more stable complex with transition metal because the metal- carbon bonds in metal carbonyls have both and characters .A bond is formed when carbonyl carbon donates a lone pair of electrons to the vacant orbital of the metal. A bond formed by the donation pair of electrons from filled metal d orbital into the vacant anti- bonding orbital ( also known as back bonding of the carbonyl group). And sigma bond strengthen the pi bond vice-versa. Thus, a synergic effect s created due to this metal- ligand bonding. These synergic effects strengthen the bond between CO and the metal.
Sponsor Area
Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i) K[Cr(H2O)2(C2O4)2], (ii) [Co(en)3Cl3,
(iii) [Co(NH3)5(NO2)]|NO3]2, (iv) [Pt(NH3)(H2O)Cl2]
Sponsor Area
Sponsor Area