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Electrochemistry
Question
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How much charge is required for the reduction of 1 mol of Zn2+ to Zn?

Answer

Zn2+ + 2e- ---> Zn
Number of electrons involved = 2
Charge required for the reduction of Zn2+ = 2F
We know
1F = 96,487 C
Thus,
2F = 2 x 96487 = 1,92,974 C

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