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Chemical Kinetics
Question
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A first order reaction has a specific reaction rate of 2.31 x 10–3 sec–1. Calculate the half-life period of the reaction.

Answer

For the first order reaction the half life can be shown written as :

t1/2 = 0.693/k

As we have given k= 2.31 x 10-3s-1

putting this value in above equation, we get

t1/2 = 0.693/2.31 x10-3s-1 = 300s

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