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The d-And-f-Block Elements
Question
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Explain:
Mn(II) shows maximum paramagnetic character amongst the divalent ions of the first transition series.

Answer

The electronic configuration of Mn is [Ar] 4s2 3d5.
In Mn(II) configuration is  [Ar] 4s0 3d5. thus  shows maximum paramagnetic character amongst the divalent ions of the first transition series because it has the largest number of unpaired electrons.

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Some More Questions From The d-And-f-Block Elements Chapter

In the series Sc (Z = 21) to Zn(Z = 30), the enthalpy of atomisation of zinc is the lowest i.e., 26, kJ mol. Why?

The E° (M2+/M) value for copper is positive (+ 0.34 V). What is possibility the reason for this? 

How would you account for the irregular variation of ionisation enthalpies (first and second) in the first series of the transition elements?

Why is the highest oxidation state of a metal exhibited in its oxide or fluoride only?

Which is a stronger reducing agent Cr2+ or Fe2+ and why?

Explain why Cu+ ion is not stable in aqueous solutions?

Actinoid contraction is greater from element to element than lanthanoid contraction. Why?

On what ground can you say that scandium (Z = 21) is a transition element but zinc (Z = 30) is not?

The outer electronic configuration of copper is 3d10 4s1, yet it is considered transition element. Why?