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States of Matter
Question
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What volume of oxygen gas (O2) measured at 0oC and 1 atm, is needed to burn completely 1 L of propane gas (C3H8)  measured under the same conditions?

  • 7 L

  • 6 L 

  • 5 L 

  • 10 L

Answer

C.

5 L 

Volume of a gas at STP = 22.4 L 
C3H 8 +    5O2 → 3CO2 + 4H2O
22.4 L       5 x 22.4 L
Therefore,
to burn 22.4 L C3H8 the oxygen required is 
 = 5 x 22.4 L 
To burn 1 L C3H8  the oxygen required will be  = 5 x 22.4 / 22.4  = 5 L 

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