☰
✕

States of Matter
Question
Wired Faculty App

20-litre container at 400 K contains CO2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the containers is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of CO2 attains its maximum value, will be

Given that: SrCO3 ⇌ SrO(s) + CO2(g) kp = 1.6 atm)

  • 5 litre

  • 10 litre

  • 8 litre

  • 3  litre

Answer

A.

5 litre

Max. the pressure  of CO2= Pressure of CO2 at equilibrium
For reaction, SrCO3 ⇌ SrO(s) + CO2(g)
Kp= PCO2 = 1.6 atm = maximum pressure of CO2
Volume Container at this stage,
V= nRT/P .... (i)

Since container is sealed and reaction was not  earlier at equilibrium
therefore, n = constant
n= Pv/RT  .... (ii)
from equation (i) and (ii) we get
V = (0.4 x 20)/RT = 5 Litre

Sponsor Area

Some More Questions From States of Matter Chapter

What is atmospheric pressure?

Which state of matter has a definite volume but no definite shape?

What is absolute temperature?

What is the absolute zero temperature?

Can absolute zero temperature be attained for a gas?

How pressure of a given sample of gas is related to absolute temperature at constant volume?

How is the pressure of a gas related to the number of molecules of the gas at constant temperature and volume?

What is standard (or normal) temperature and pressure (STP)?

What does SATP stand for? Define it.