Equilibrium

Question

HgCl2 and I2 both when dissolved in water containing I ions the pair of species formed is

  • HgI2 , I3-

  • Hgl2, I-

  • HgI43-, I3-

  • Hg2I2, I-

Answer

C.

HgI43-, I3-

In a solution containing HgCl2, I2 and I–, both HgCl2 and I2
compete for I.
Since formation constant of [HgI4]2– is 1.9 × 1030
which is very large as compared with I3 (Kf= 700)
therefore, I will preferentially combine with HgCl2
HgCl2 + 2l- → Hgl2↓ + 2Cl-
Hgl2 + 2l- → [Hgl4]2-

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