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Reducing property. The order of increasing reducing character is: H 2 O < MgH 2 < NaH Reason: NaH being an ionic hydride, therefore it is a powerful reducing agent. On the other hand, both MgH 2 and H 2 O are covalent hydrides, but the bond dissociation energy of H 2 O is more than that of MgH 2 . Hence the reducing character increases in the order: H 2 O < MgH 2 < NaH

Hydrogen

Question

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Arrange the following:

NaH, MgH₂ and H₂O in order of increasing reducing property.

Answer

Reducing property. The order of increasing reducing character is:
H₂O < MgH₂ < NaH
Reason: NaH being an ionic hydride, therefore it is a powerful reducing agent. On the other hand, both MgH₂ and H₂O are covalent hydrides, but the bond dissociation energy of H₂O is more than that of MgH₂. Hence the reducing character increases in the order:
H₂O < MgH₂ < NaH