Trying to find the right answer to this..

Let x be the oxidation number of P. Oxidation number of Ba =+2 Oxidation state of O 2 =-2 Thus, oxidation number of P in Ba(H 2 PO 2 ) 2 +2 + 4(1) + 2x + 4(-2) = 0 or 2x - 2 = 0 or x = + 1

Redox Reactions

Question

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Calculate the oxidation number of P in Ba(H₂PO₂)₂.

Answer

Let x be the oxidation number of P.
Oxidation number of Ba =+2
Oxidation state of O₂ =-2
Thus, oxidation number of P in Ba(H₂PO₂)₂ +2 + 4(1) + 2x + 4(-2) = 0
or 2x - 2 = 0 or x = + 1