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Equilibrium

Question

Arrange the following in decreasing order of acidic strength:
(i) HOCl (K_a = 3·0 × 10^–8)
(ii) HCN (K_a = 4·0 × 10^–10)
(iii) HNO₃ (K_a = 4·5 × 10^–4)
(iv) HF (K_a = 6·7 × 10^–4)

Answer

Greater the K_a value, stronger will be the acid.
∴
Decreasing order of acidic strength is
HF > HNO₃ > HOCl > HCN.

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Entrance Exams Preparation

Arrange the following in decreasing order of acidic strength:
(i) HOCl (K_a = 3·0 × 10^–8)
(ii) HCN (K_a = 4·0 × 10^–10)
(iii) HNO₃ (K_a = 4·5 × 10^–4)
(iv) HF (K_a = 6·7 × 10^–4)

Some More Questions From Equilibrium Chapter

Mock Test Series

NCERT Book Store

NCERT Sample Papers

Entrance Exams Preparation

Arrange the following in decreasing order of acidic strength:(i) HOCl (Ka = 3·0 × 10–8)(ii) HCN (Ka = 4·0 × 10–10)(iii) HNO3 (Ka = 4·5 × 10–4)(iv) HF (Ka = 6·7 × 10–4)

Some More Questions From Equilibrium Chapter

Mock Test Series

NCERT Book Store

NCERT Sample Papers

Entrance Exams Preparation

Arrange the following in decreasing order of acidic strength:
(i) HOCl (K_a = 3·0 × 10^–8)
(ii) HCN (K_a = 4·0 × 10^–10)
(iii) HNO₃ (K_a = 4·5 × 10^–4)
(iv) HF (K_a = 6·7 × 10^–4)