Chemical Bonding and Molecular Structure
The elements present in the third period contain a-orbitals in addition to s and p orbitals.
The energy of the 3d orbitals is comparable to,
(i) the energy of 3s and 3p orbitals
(ii) the energy of 4s and 4p orbitals.
Hence the hybridization involving either 3s, 3p and 3d or 3d, 4s and 4p is possible. However, since the difference in energies of 3p and 4s orbitals is significant, therefore no hybridization involving 3p, 3d and 4s orbitals is possible.
The hybridisation schemes involving s, p and d orbitals are summarised below:
Shape of molecules/ions | Hybridisation type | Atomic obritals | Examples |
Squre planar | dsp2- | d+s+p(2) |
[Ni(CN)4]2–, [Pt(Cl)4]2– |
Trigonal Bipyramdial | sp3d | s+p(3)+d | PF5.PCl5 |
Square pyramidal | dsp3 | d+s+p( 3) | BrF5,XeOF4 |
Octahedral | sp3d2 | s+p(3)+d(2) | SF6,[CrF6]3– |
d2 sp3 | d(2)+s+p(3) |
[Co(NH3)6]3+ |
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What are 'Lewis structures'?
Name the conditions for the formation of an ionic bond between two atoms.
What is crystal lattice?
What is electrovalency?
What bond is present in MgCl2 molecules?
Two elements A and B have the electronic configuration as:
A = 1s22s22p63s2 and B = 1s22s22p5
Write the empirical formula of the substance containing A and B.
What type of bonding would you expect between:
(i) a metal and a non-metal
(ii) a non-metal and another non-metal?
Give reasons in one or two sentences for the observation that in their compounds non-metals form anions and not cations.
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