-->

त्रिकोणमिति का परिचय

Question
CBSEHHIMAH10010223

यदि tan space left parenthesis straight A plus straight B right parenthesis space equals space square root of 3 और tan left parenthesis straight A minus straight B right parenthesis space equals space fraction numerator 1 over denominator square root of 3 end fraction0 degree less than straight A plus straight B less or equal than 90 degree semicolon space space straight A greater than straight B तो A और B का मान ज्ञात कीजिए।

Solution
tan left parenthesis straight A plus straight B right parenthesis space equals space square root of 3
tan left parenthesis straight A plus straight B right parenthesis space equals space tan space 60 degree
⇒ A + B = 60° ...(i)
और 
tan left parenthesis straight A minus straight B right parenthesis space equals space fraction numerator 1 over denominator square root of 3 end fraction
tan left parenthesis straight A minus straight B right parenthesis space equals space tan space 30 degree
⇒ A - B = 30° ...(ii)
समीकरण (i) तथा (ii) को हल करने पर हमें प्राप्त होता हैं:
A = 45° and B = 15°.

Some More Questions From त्रिकोणमिति का परिचय Chapter