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त्रिकोणमिति का परिचय

Question
CBSEHHIMAH10010234

यदि A, B और C त्रिभुज ABC के अंत:कोण हों,तो दिखाइए कि:  
          space sin space open parentheses fraction numerator straight B plus straight C over denominator 2 end fraction close parentheses space equals space cos straight A over 2

Solution

त्रिभुज ABC, हमें प्राप्त हैं:
            straight A plus straight B plus straight C space equals space 180 degree
rightwards double arrow space space space space space straight B plus straight C space equals space 180 degree space minus straight A space space space space space... left parenthesis straight i right parenthesis
space space space space space space space space space space space space space space space space space space space space space space space left square bracket उपर ो क ् त space सम ी करण space क ो space left parenthesis 2 right parenthesis space स े space भ ा ग space करन े space पर space right square bracket space space space space space space space space space space space space space space space space space space space space space space space space space space space space space
rightwards double arrow space space space space fraction numerator space straight B plus straight C over denominator 2 end fraction space equals space fraction numerator 180 degree space minus space straight A over denominator 2 end fraction

rightwards double arrow space space space space space space space space sin space open parentheses fraction numerator straight B plus straight C over denominator 2 end fraction close parentheses space equals space sin space open parentheses 90 degree minus straight A over 2 close parentheses
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets because space sin space left parenthesis 90 degree minus straight theta right parenthesis space equals space cos space straight theta close square brackets
rightwards double arrow space space space space space space space space space sin open parentheses fraction numerator straight B plus straight C over denominator 2 end fraction close parentheses space equals space cos straight A over 2

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