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Electrostatic Potential And Capacitance

Question
CBSEENPH12039994

Two positive ions, each carrying a charge q, are separated by a distance d. If F is the force of repulsion between the ions, the number of electrons missing from each ion will be (e being the charge on an electron)

  • fraction numerator 4 πε subscript straight o Fd squared over denominator straight e squared end fraction
  • square root of fraction numerator 4 πε subscript straight o Fe squared over denominator straight d squared end fraction end root
  • square root of fraction numerator 4 πε subscript straight o Fd squared over denominator straight e squared end fraction end root
  • fraction numerator 4 πε subscript straight o Fd squared over denominator straight q squared end fraction

Solution

C.

square root of fraction numerator 4 πε subscript straight o Fd squared over denominator straight e squared end fraction end root

Two positive ions each carrying a charge q are kept at a distance d, then it is found that force of repulsion between them is
straight F space equals space kqq over straight d squared
equals space fraction numerator 1 over denominator 4 πε subscript straight o end fraction qq over straight d squared
where space straight q space equals ne

straight F space equals space fraction numerator 1 over denominator 4 πε subscript straight o end fraction fraction numerator straight n squared straight e squared over denominator straight d squared end fraction
straight n equals square root of space fraction numerator 4 πε subscript straight o Fd subscript 2 over denominator straight e squared end fraction end root

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