Question
A source S1 is producing, 1015 photons of wavelength 500 A. Another source S2 is producing 1.02 x 1015 photons per second of wavelength 5100 A. Then, power of S2) (power of S1) is equal to
-
1.00
-
1.02
-
1.04 A
-
0.98
Solution
A.
1.00
Number of photons emitted per seconds 
